Dec 17, 2003 #1 hodeez Messages 28 Reaction score 0 Hi guys, I have a calculus test tomorrow and it'll be great if I can receive some answers + explanations! my review sheet is attached. if this is breaking the rules I am sorry. hope this actually helps some other people too Attachments reviewsheet.doc reviewsheet.doc 39.5 KB · Views: 282 Last edited: Dec 17, 2003
Hi guys, I have a calculus test tomorrow and it'll be great if I can receive some answers + explanations! my review sheet is attached. if this is breaking the rules I am sorry. hope this actually helps some other people too
Dec 17, 2003 #2 hodeez Messages 28 Reaction score 0 for #1 i got 3x^2-sin(xy^2)*2xy [dy/dx]*y^2 whadaya thinks?
Dec 17, 2003 #3 hodeez Messages 28 Reaction score 0 for #2) its log(x)/log4 b)then graph it with my TI89 then find the deriv @ .4 at work right now so no calculator on me =) btw: does the TI89 have a test function == like the ti86?
for #2) its log(x)/log4 b)then graph it with my TI89 then find the deriv @ .4 at work right now so no calculator on me =) btw: does the TI89 have a test function == like the ti86?
Dec 17, 2003 #4 hodeez Messages 28 Reaction score 0 #3) f'(x)=2+cosx so we have to prove f'(x) is constantly positive or negative.. but how would we approach that?
#3) f'(x)=2+cosx so we have to prove f'(x) is constantly positive or negative.. but how would we approach that?
Dec 17, 2003 #5 NateTG Science Advisor Homework Helper Messages 2,449 Reaction score 7 Originally posted by hodeez #3) f'(x)=2+cosx so we have to prove f'(x) is constantly positive or negative.. but how would we approach that? What's the minimum of cos(x) (assuming x is real)
Originally posted by hodeez #3) f'(x)=2+cosx so we have to prove f'(x) is constantly positive or negative.. but how would we approach that? What's the minimum of cos(x) (assuming x is real)
Dec 17, 2003 #6 hodeez Messages 28 Reaction score 0 Originally posted by NateTG What's the minimum of cos(x) (assuming x is real) sorry I am not quite following you. on the y-axis it is -1, and on the x it can be -infinite. please correct me if I am wrong
Originally posted by NateTG What's the minimum of cos(x) (assuming x is real) sorry I am not quite following you. on the y-axis it is -1, and on the x it can be -infinite. please correct me if I am wrong
Dec 17, 2003 #7 NateTG Science Advisor Homework Helper Messages 2,449 Reaction score 7 So, if the minimum value of cos(x) is -1, what is the minimum value of 2+cos(x)?
Dec 17, 2003 #8 hodeez Messages 28 Reaction score 0 lol wow i feel so dumb thanks onward to the next question after i finish some quick job for my boss.
Dec 17, 2003 #9 hodeez Messages 28 Reaction score 0 i got x-4=y^3+y so turn my ti89 to parametric mode and y1 = t^3+t y2= -1 right? (since its g(3) 3-4 = -1) then i trace for a zero? Last edited: Dec 17, 2003
i got x-4=y^3+y so turn my ti89 to parametric mode and y1 = t^3+t y2= -1 right? (since its g(3) 3-4 = -1) then i trace for a zero?
Dec 18, 2003 #10 hodeez Messages 28 Reaction score 0 just came back from my test and i got confused on a question... find the deriv of x+sin(xy) i got (-sec(x)-y)/x but the calc gave me 1 thanks to all the people that replied and (attempted to) help
just came back from my test and i got confused on a question... find the deriv of x+sin(xy) i got (-sec(x)-y)/x but the calc gave me 1 thanks to all the people that replied and (attempted to) help
Dec 19, 2003 #12 hodeez Messages 28 Reaction score 0 oh my goddd what did i do? i messed up.. oh wells thanks himanshu121 for reminding me of my errror