Calorimetry Calibration: Find qrxn, qcal, and Ccal with NaOH and HCl

AI Thread Summary
To solve for qrxn, qcal, and Ccal in the reaction between NaOH and HCl, the key is to utilize the given volumes and concentrations of the reactants. The temperature change of 2.1°C is critical for calculating qcal using the equation Ccal = qcal/∆T. The total mass can be estimated by assuming a density of 1 g/mL for the solution, allowing for the determination of the heat absorbed or released. The relationship qrxn = -qcal indicates that the heat of the reaction is equal in magnitude but opposite in sign to the heat absorbed by the calorimeter. With all necessary data available, the problem can be solved effectively.
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Homework Statement


in the reaction 10mL of 1M NaOH + 5mL of 1M HCl (adiabatic)
given change in temp=2.1°C (temp initial is the temp of NaOH, temp final is acquired after the addition of HCl)
find: qrxn, qcal, Ccal


Homework Equations


qrxn = -qca
Ccal = qcal/∆T


The Attempt at a Solution


sorry but I'm really at total lost here. i took the prerequisite chemistry 4semesters ago
the only thing that i can find in searching are the formula on how to solve them but i can't quite get how to use those given only the dT
 
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You are given much more - you know the volumes, you know concentrations (that gives amounts of acid and base), assuming density of 1 g/mL (often done for not too concentrated water solutions) you have also total mass. Plenty of data to solve the question.
 

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