Can 4/3(sin theta) = theta be algebraically solved?

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The equation 4/3(sin theta) = theta cannot be solved algebraically, and the best approach is to find an approximate solution using numerical methods. The Newton-Raphson method is suggested as a viable option for obtaining an approximation. Some users attempted to use Maclaurin's series, yielding an approximate answer of 1.28, though this method is considered tedious. The discussion also highlights issues with accessing external resources for further clarification. Ultimately, there is consensus that no analytical solution exists for the equation.
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those above steps imo are unnecessary, all i need to know is how to solve 4/3(sin theta)=theta, thanks in advance!
 
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Two things:
  1. Is your equation 4/3 * sin(theta) = theta or is it 4/[3 sin(theta)] = theta?
  2. You are not going to be able to solve your equation, whichever one it is, by algebraic means. The best you can do is to get an approximate solution.
 


The link you gave is broken, so I don't know what you meant to show me. In any case, what I said in post 2 still applies.
 


its not broken, all you have to do is click on the address bar and press enter, as if you were typing the url in.
 


Mark44 said:
The link you gave is broken, so I don't know what you meant to show me. In any case, what I said in post 2 still applies.
choob is actually right, you have to do something like copying and pasting the URL instead of just following the link. The site is probably trying to prevent direct linking.

Anyway, the PDF file doesn't change anything - there is no analytic solution. You would need to use a graphing calculator or a computer to find the answer. (There's probably some sort of series expansion trick or something you could use to get a good approximation by hand)
 


If it's 4/3 * sin(theta) = theta you can find one pretty obvious solution.
 
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freeexampapers has had a lot of bandwidth problems. We welcome direct linking and plan to have enough bandwidth to allow this.
 


Cyosis said:
If it's 4/3 * sin(theta) = theta you can find one pretty obvious solution.

Hi Cyosis ! I took some time looking and pondering of the possible solution and i could not figure it out , I hope you can provide me of the partial solution. Thank you.
 
  • #10


Can somebody explain what's the task?
 
  • #11


Дьявол said:
Can somebody explain what's the task?

solve for theta
 
  • #12


i tried using maclaurin's series and i manage to work out with the answer of 1.28 but i guess it is rather tedious.
 
  • #13


icystrike said:
i tried using maclaurin's series and i manage to work out with the answer of 1.28 but i guess it is rather tedious.

Well you could use the Newton-Raphson iterative method and find an approximation.
 
  • #14


rock.freak667 said:
Well you could use the Newton-Raphson iterative method and find an approximation.

Yes indeed Newton Raphson method can solve and it is similar to taylor'series.
Is there any other method to solve this question algebraically?
 
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  • #15


No.
Yes, I was also quite dissappointed to hear that such a simple result such as the one you have presented has no means of being algebraically solved; but what can you do...
 
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