Can a Car Safely Turn on a 40-Degree Banked Road at 30 m/s?

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A car can safely navigate a banked road at a 40-degree angle while traveling at 30 m/s if the friction coefficient is 0.6 and the turn radius is 100 m. To analyze this, one must draw a force diagram that includes gravitational forces and the components of centripetal acceleration. The forces acting on the car can be resolved into components along the incline and perpendicular to it. If the combined downward force from gravity and friction is adequate to counteract the centripetal force required for the turn, the car will not slip. Proper calculations are essential to confirm the safety of the turn under these conditions.
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Homework Statement



Will a road banked at 40 degrees allow cars (u=0.6) to safely make a turn (radius=100m) while traveling at 30 m/s (or 67 mi/hr)?

Homework Equations



f = uN
possibly others

The Attempt at a Solution



I'm really not sure how to get started. This is the only problem I don't know how to do. I would really appreciate any help. Thank you.
 
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Welcome to PF.

Draw a force diagram on the car.

Gravity is vertically down, so the components of weight can be resolved as vectors along the incline and normal to the incline.

The centripetal acceleration is acting horizontally. Its components can also be resolved along the plane of the incline and normal to it.

If the downward force of gravity and the additional maximum contribution from the friction component is sufficient to prevent the car from slipping then ...
 
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