Can a Continuous Function Map One Value to Two Different Points?

za10
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Homework Statement



Show that a continuous function such that for all c in the reals, the equation f(x) = c cannot have two solutions

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The Attempt at a Solution



I was thinking along the lines of a contradiction or somehow using intermediate value theorem but it seems like it is so easy it is hard.
 
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What are you actually trying to prove here? Your sentence doesn't parse properly
 
show that a continuous function cannot have two solutions for the equation f(x) = c for every c.
 
I have f(x) = c... am I solving for x given c? What you're trying to say is that f can't be two to one (i.e. for every point p in the image, there are two points in the preimage of p).

Contradiction is a good place to start. There have to be two points that f maps to zero, consider f on the interval between them
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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