Can a Matrix with Identical Columns be Invertible?

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An nxn matrix with two identical columns cannot be invertible because such columns are linearly dependent. If the columns are not linearly independent, the matrix fails to meet the criteria for invertibility. A key point in proving this is that if a nonzero vector x exists such that Ax=0, then the matrix A is not invertible. Additionally, the determinant of a matrix with identical columns is zero, further confirming its non-invertibility. Understanding the relationship between linear independence and the structure of the matrix is crucial in this proof.
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i need to be able to prove that an nxn matrix with two identical columns cannot be invertible. I know that if the columns of the matrix are linearly independent then the matrix is invertible. Could some please give me a hint on how to do this proof because i really don't know where to start. :frown:
 
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Depending on what has been covered in your class, it may be easiest to work with the nullspace of the matrix A. A is invertible iff the nullspace of A contains only the zero vector.
Call, the matrix A. If you can find a nonzero vector x such that Ax=0, then you've shown A is not invertible.
 
As Galileo said, it depends on what has been covered. It is relatively easy to show that the determinant of a matrix in which two columns are the same is 0.
 
Chadlee88 said:
i need to be able to prove that an nxn matrix with two identical columns cannot be invertible. I know that if the columns of the matrix are linearly independent then the matrix is invertible. Could some please give me a hint on how to do this proof because i really don't know where to start. :frown:

what's it mean when two columns of a matrix are identical?

Compare this with what is meant by 'linearly independent'.

Can two identical columns in one matrix be independent?
 
Actually, I've never seen a text that definedf "independent" for the columns of a matrix!

You can, of course, think of the columns of a matrix as vectors and then determine whether or not those vectors are independent.
 
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hallsofivy, I think the columns being independent refers to them as vectors being linearly independent essentially (it's not proper terminology perhaps, but it does get the point across)
 
Office_Shredder said:
hallsofivy, I think the columns being independent refers to them as vectors being linearly independent essentially (it's not proper terminology perhaps, but it does get the point across)
Yeh, I went back and edited my post just before I saw this.
 
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