Can a paper and tape tower hold 1 L of water for more than 1 minute?

AI Thread Summary
The discussion centers on constructing a paper and tape tower that meets specific criteria: it must be 1.5 meters tall, hold 1 liter of water for over a minute, and be built solely from paper and tape within five minutes. The original poster has experimented with various designs but finds them either too time-consuming or not sturdy enough. Suggestions include using large rolls of newsprint to create a taller, more stable structure. Clarification is sought regarding any limitations on the dimensions of the paper used. Effective design and material choice are crucial for success in this challenge.
Endorser
Messages
41
Reaction score
0
As part of an assignment, I have been asked to construct a tower that is completely made of paper and sticky tape. This tower must be built with 4 specifications:

1. Must be built of nothing but paper and tape no cutting devices, glue, ect ect.
2. Must be built within 5 minutes.
3. Must be able to hold 1 L of water on the top for more than 1 minute.
4. Must be 1.5m tall.

I have tried a range of difference shapes and designs but they all take too long or are too flimsy.

All assistance is welcome!

Thanks
 
Physics news on Phys.org
What have you tried?
 
I have seen trucks going by carrying 3 huge rolls of newsprint, each much longer than 1.5m. Maybe a shortened one of these, standing on end, will do the job? No glue or sticky tape needed.

Is there a limit to the dimensions of the sheet of paper?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top