Can a Single Galaxy Estimate Provide an Accurate H0 Value?

  • Thread starter Thread starter b_o3
  • Start date Start date
  • Tags Tags
    Galaxy
AI Thread Summary
The discussion revolves around estimating the Hubble constant (H0) using the Milky Way's velocity of 310 km/s as it falls into a galaxy cluster. Participants are prompted to apply Hubble's law, which relates the velocity of a galaxy to its distance from Earth, to derive an H0 value. The conversation seeks input on calculations and methodologies for this estimation. The accuracy of using a single galaxy for such a significant cosmological constant is also questioned. Ultimately, the thread encourages collaboration and sharing of approaches to solve the problem.
b_o3
Messages
52
Reaction score
0
can anyone help me out with this:

Assuming that our milky way is falling into this cluster with a velocity of 310 km/s due to gravitational attraction , estimate a value for H0 (in km s^ -1 Mpc^-1) using this single galaxy.
 
Physics news on Phys.org
What is your attempt? Do you know Hubble's law?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top