Can a Tetrahedron be Constructed with the Given Equation in Natural Numbers?

disregardthat
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Hi, I was wondering if anyone could find a solution to this:

d^2-ab=e^2-bc=f^2-ac

in the natural numbers where not all variables are equal. I don't know how to make a computer program, but if it takes little time, I would really appreciate if I could have a solution to it.
 
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Let a, b, and c be any square numbers, and let d, e, and f be defined so that the differences are zero. The rest is trivially obvious.

If you want non-zero differences it will be more complicated.
 
Of course =) thanks (cant believe i didn't think of that)

Any solution a,b,c,d,e,f gives a tetrahedron of side lengths a,b,c,d,e,f where a sphere may be located within touching all sides - if my calculations are correct.
 
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I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
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