Can a Tower of Books Move with Lighter Forces?

  • Context: Undergrad 
  • Thread starter Thread starter Clockclocle
  • Start date Start date
  • Tags Tags
    Books Forces Tower
Click For Summary
SUMMARY

The discussion centers on the mechanics of a stack of books and the forces required to move them. It establishes that the last book in the stack exerts a force of N=nmg on the surface, where n is the number of books and mg is the weight of each book. The conversation clarifies that the term "last book" refers to the bottom book in the stack, which is crucial for understanding the distribution of forces. It concludes that applying a force at the bottom book can facilitate movement of the entire stack, but the method of force application significantly impacts the ease of movement due to torque and weight distribution.

PREREQUISITES
  • Understanding of static friction and force distribution
  • Basic principles of mechanics, including torque
  • Knowledge of compressibility in materials
  • Familiarity with the concept of center of mass
NEXT STEPS
  • Research the effects of torque on object movement
  • Study the principles of static friction in stacked objects
  • Explore the mechanics of force application on different points of an object
  • Learn about the properties of compressible versus incompressible materials
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the principles of force and motion in stacked systems.

Clockclocle
Messages
31
Reaction score
1
Suppose n book stack on each other. Since each book have the same weigh then the last book exert a force N=nmg on the surface so it has the biggest static friction. But if we treat the whole tower of books as one particle it also has N=nmg. This mean if we exert enough force in the last book, the tower keep moving as we exert lighter force on all the book at the same time?
 
Physics news on Phys.org
Clockclocle said:
the last book exert a force N=nmg on the surface
The last book does not make contact with the surface. It exerts a friction force only on the book it's on top of.

##\ ##
 
  • Like
Likes   Reactions: topsquark
BvU said:
The last book does not make contact with the surface. It exerts a friction force only on the book it's on top of.
What? I think the last book would both contact with the surface and the top of it?
 
I think the OP is using "last book" to mean the one at the bottom of the stack. (I would call the top one the last book, since it was the last one placed on the stack, but the question makes more sense if it means the bottom book.)

In that case, the answer to the question depends on what idealisation you make. If you idealise the books as non-compressible and much wider than the stack is tall so there's no significant difference in torque between the two cases, then yes you can get the same motion by applying ##n## forces of magnitude ##F## or one of magnitude ##nF##.

In reality, books are typically slightly compressible and a stack of books will frequently be taller than it is wide. In that case where you apply the force matters because it will change how the weight is distributed which may affect how easily it slides. It's a fairly common experience that pushing something at a point below its center of mass is easier than pushing it at the top.
 
Last edited:
  • Like
Likes   Reactions: BvU
Clockclocle said:
Suppose n book stack on each other
This is not possible: you can place a book on top of another book, but then the lower book is not on top of the top one. language .. :rolleyes:

Clockclocle said:
What? I think the last book would both contact with the surface and the top of it?
It seems we mean different things when we mention 'the last book'. language ... :rolleyes:

Easier to only use 'top book' and 'bottom book'. Even better to make a sketch to clarify.

Clockclocle said:
This mean if we exert enough force in the last book, the tower keep moving as we exert lighter force on all the book at the same time?
Could you now clarify your question ? I have difficuty understanding the last part...

(and let's assume the books all behave as identical ideal incompressible blocks, with a friction coefficient ##\mu## -- both between books and between bottom book and table. OK?)

##\ ##
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K