MHB Can an algebraic expression be made here.

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An algebraic expression can be formed to determine the number of mandarins and guavas that can be bought for 50. The equation is 20M + 15G = 50, which simplifies to 4M + 3G = 10. This represents a Diophantine equation, indicating that integer solutions exist for M and G. The discussion confirms that this is the maximum simplification of the equation. The focus remains on finding the integer combinations of mandarins and guavas within the given budget.
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The price of a mandarin is 20 and the price of a guava is 15. Find the number of mandarins and guavas that can be bought for 50.

(Thinking) So can an algebraic expression be made and the number of mandarin's and guavas that can be bought for 50.

Many Thanks (Happy)
 
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Well, let $M$ be the number of mandarins and $G$ be the number of guavas, then we have:

$$20M+15G=50$$

Divide through by 5:

$$4M+3G=10$$

This is a Diophantine equation.
 
MarkFL said:
Well, let $M$ be the number of mandarins and $G$ be the number of guavas, then we have:

$$20M+15G=50$$

Divide through by 5:

$$4M+3G=10$$

This is a Diophantine equation.

Many Thanks (Happy), So I see that this is the maximum the equation can be simplified.
 
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