Can anyone help me check my free body diagram for mobile crane

AI Thread Summary
The discussion focuses on reviewing a free body diagram for a mobile crane, with participants providing feedback on the accuracy of force directions. It is noted that some forces may be incorrectly shown but can be adjusted in calculations without significant issues. Clarification is sought on the definitions of forces in the diagram, particularly regarding vertical forces exerted by the girder and the base. The importance of ensuring that forces from the ground on the wheels are correctly represented to maintain stability is emphasized. Overall, the conversation highlights the need for precision in isolating forces when drawing free body diagrams.
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Your diagram looks ok. Some forces are shown going the opposite way to what will actually happen, but that won't matter - they'll just come out negative. you won't be needing Rpx.
 
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haruspex, can you tell me which are the force going the opposite way? I need to learn from my mistake. so please guide me thanks
 
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cracktheegg said:
haruspex, can you tell me which are the force going the opposite way? I need to learn from my mistake. so please guide me thanks
As I wrote, it doesn't really matter. As long as you apply the chosen directions consistently in the equations it will come out fine. Remember that there will be situations where it is not obvious which way the force will act, so it's rather important that it is not necessary to guess it correctly. (An exception to this is friction. You may sometimes need to consider two possibilities separately.)

In the diagram you posted, it's not always clear how a force is being defined. E.g. consider R2y. Is that a vertical force exerted by the girder on the base, or an (equal and opposite) force exerted by the base on the girder? Whichever it is, I assume R3y is defined similarly. Now compare R2y and R3y. You show both pointing down. They must be in fact be in opposite directions to counter the moment from the load.
 
haruspex said:
As I wrote, it doesn't really matter. As long as you apply the chosen directions consistently in the equations it will come out fine. Remember that there will be situations where it is not obvious which way the force will act, so it's rather important that it is not necessary to guess it correctly. (An exception to this is friction. You may sometimes need to consider two possibilities separately.)

In the diagram you posted, it's not always clear how a force is being defined. E.g. consider R2y. Is that a vertical force exerted by the girder on the base, or an (equal and opposite) force exerted by the base on the girder? Whichever it is, I assume R3y is defined similarly. Now compare R2y and R3y. You show both pointing down. They must be in fact be in opposite directions to counter the moment from the load.
Where should the cg be?
 
cracktheegg said:
Where should the cg be?

CG of what? Your W1, W2, W3 and W4 look right.
 
haruspex said:
CG of what? Your W1, W2, W3 and W4 look right.


Okay Ty, now I just worry about wether should I include the wheel. Because my classmate said the wheel should be in contact with ground, there are no outrigger or hydraulic, it is just stabilizer
 
cracktheegg said:
Okay Ty, now I just worry about wether should I include the wheel. Because my classmate said the wheel should be in contact with ground, there are no outrigger or hydraulic, it is just stabilizer
There are forces from the ground surface on both the front and rear sets of wheels. One has to be certain that the vertical force from the ground on the rear wheels is upward, or else the rear wheels would lose contact with the ground and the crane would become unstable and start to tip over.
You have to be careful in drawing free body diagrams to isolate the members or joints you are interested in. For example, when looking at the entire crane system, the only forces acting are the weight forces and the reaction forces from the wheels. All other forces are internal to the system. It is not good practice to show all forces internal and external on one diagram without breaking up the system into its parts.
 
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Thanks a lot guys, i learn alot
 
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