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Can I assume that the velocity is the same?

  1. May 12, 2015 #1
    1. The problem statement, all variables and given/known data
    Calculate "H"
    upload_2015-5-12_17-17-36.png

    2. Relevant equations
    Bernoulli
    Manometry

    3. The attempt at a solution
    I have calculated that Q=0.06723 m^3 /s
    If I apply Bernoulli in the surface of the tank A and in out of the pipe, I have: H =(velocity in the final part of the pipe^2)/(2g). I have assumed that the Velocity in the final part of the pipe It is the same velocity with which the water comes out. I did this because I can't know the presurre in the final part of the pipe, and out of the pipe the manometric pressure is zero.

    So MY QUESTION IS: Is correct to assume that the velocities at these points (in the final part of the pipe, and just outside the pipeline are the same??
     
  2. jcsd
  3. May 12, 2015 #2
    Sure, if you're neglecting the viscous frictional pressure loss.

    Chet
     
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