IooqXpooI
- 54
- 0
(Sorry, I'm testing with the 'tex' code)
Reverse Gravitational Force is the opposite force of Gravity.
It is it that keeps two bodies from not moving EXACTLY into the areas given by F=\frac {G_m_1_m_2} {r^2}...
You can test it by using EXTREMELY precise instruments, and checking if an object on a seesaw with its more massive counterpart align exactly to form a perfectly balanced seesaw.(Of course, you put friction into the picture...duh
)
Reverse Gravity applies to both objects(in a two body system)...(By the way)
Here are the equations...they may be flawed(of course, this all may be untrue!
)...
R_g_1=\frac{r^2}{Gm_1^2}
R_g_2=\frac{r^2}{Gm_2^2}
D_t_1=\frac{t(R_g_1)}{m}
D_t_2=\frac{t(R_g_2)}{m}
T_D_t_1=t(F_2-R_g_1)
T_D_t_2=t(F_1-R_g_2)
R_g_i_t_b=\frac{r^2}{Gm_1m_2}<br /> <br /> Hope that's correct!(Lemme go check my notebook...)<br /> <br /> Where F equals Gravitational Force, R_g equals Reverse Gravitational Force(with distinctions of which body it is applying to), D_t equals the Distance traveled because of the Reverse Gravitational force(again with distinctions), R_g_i_t_b equals the Reverse Gravity in two bodies, T_D_t equals the total distance traveled because of Gravity and Reverse Gravity, G equals Newton's Gravitational Constant, m_1 equals the mass of the more massive body, and m_2 equals the mass of the less massive body.<br /> <br /> By the way, this has been edited from its original content to fit the screen of your brain. :p<br /> <br /> Though I did edit this.
Reverse Gravitational Force is the opposite force of Gravity.
It is it that keeps two bodies from not moving EXACTLY into the areas given by F=\frac {G_m_1_m_2} {r^2}...
You can test it by using EXTREMELY precise instruments, and checking if an object on a seesaw with its more massive counterpart align exactly to form a perfectly balanced seesaw.(Of course, you put friction into the picture...duh

Reverse Gravity applies to both objects(in a two body system)...(By the way)
Here are the equations...they may be flawed(of course, this all may be untrue!

R_g_1=\frac{r^2}{Gm_1^2}
R_g_2=\frac{r^2}{Gm_2^2}
D_t_1=\frac{t(R_g_1)}{m}
D_t_2=\frac{t(R_g_2)}{m}
T_D_t_1=t(F_2-R_g_1)
T_D_t_2=t(F_1-R_g_2)
R_g_i_t_b=\frac{r^2}{Gm_1m_2}<br /> <br /> Hope that's correct!(Lemme go check my notebook...)<br /> <br /> Where F equals Gravitational Force, R_g equals Reverse Gravitational Force(with distinctions of which body it is applying to), D_t equals the Distance traveled because of the Reverse Gravitational force(again with distinctions), R_g_i_t_b equals the Reverse Gravity in two bodies, T_D_t equals the total distance traveled because of Gravity and Reverse Gravity, G equals Newton's Gravitational Constant, m_1 equals the mass of the more massive body, and m_2 equals the mass of the less massive body.<br /> <br /> By the way, this has been edited from its original content to fit the screen of your brain. :p<br /> <br /> Though I did edit this.
Last edited: