Can Reverse Gravitational Force be Used for Interstellar Travel?

AI Thread Summary
Reverse Gravitational Force is proposed as a concept that opposes traditional gravitational force, potentially allowing for interstellar travel. The discussion includes equations that attempt to quantify this force and its effects on two-body systems, emphasizing the need for precise measurements. The conversation also touches on the distinction between inertial mass and gravitational mass, particularly in relation to photons, which are theorized not to be affected by gravity. Additionally, the idea of two types of mass—potential and kinetic—is introduced, suggesting that mass has a minimum value but no maximum. The overarching question remains how to amplify Reverse Gravitational Force to enable practical space travel.
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(Sorry, I'm testing with the 'tex' code)

Reverse Gravitational Force is the opposite force of Gravity.

It is it that keeps two bodies from not moving EXACTLY into the areas given by F=\frac {G_m_1_m_2} {r^2}...

You can test it by using EXTREMELY precise instruments, and checking if an object on a seesaw with its more massive counterpart align exactly to form a perfectly balanced seesaw.(Of course, you put friction into the picture...duh :-p )

Reverse Gravity applies to both objects(in a two body system)...(By the way)

Here are the equations...they may be flawed(of course, this all may be untrue! :wink: )...


R_g_1=\frac{r^2}{Gm_1^2}
R_g_2=\frac{r^2}{Gm_2^2}
D_t_1=\frac{t(R_g_1)}{m}
D_t_2=\frac{t(R_g_2)}{m}
T_D_t_1=t(F_2-R_g_1)
T_D_t_2=t(F_1-R_g_2)
R_g_i_t_b=\frac{r^2}{Gm_1m_2}<br /> <br /> Hope that&#039;s correct!(Lemme go check my notebook...)<br /> <br /> Where F equals Gravitational Force, R_g equals Reverse Gravitational Force(with distinctions of which body it is applying to), D_t equals the Distance traveled because of the Reverse Gravitational force(again with distinctions), R_g_i_t_b equals the Reverse Gravity in two bodies, T_D_t equals the total distance traveled because of Gravity and Reverse Gravity, G equals Newton&#039;s Gravitational Constant, m_1 equals the mass of the more massive body, and m_2 equals the mass of the less massive body.<br /> <br /> By the way, this has been edited from its original content to fit the screen of your brain. :p<br /> <br /> Though I did edit this.
 
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Can I still go out of the door and remain where I'd like to be?
 
arildno said:
Can I still go out of the door and remain where I'd like to be?
LOL!

Sure!

;)
 
:-p

Finally got it!
 
Anyone Here?
 
Antimatter and matter possesses inertial mass which is equivalent to gravitational mass. Due to this mass property they are both affected by gravity. But pure bosonic particles (e.g. photons) according to my research should not have inertial or gravity mass hence cannot be affected by gravity. The mass of the photon is defined as the kinetic mass (mass of motion in contrast to inertial mass as mass of rest). When there is kinetic mass, concept of momentum can be defined.

Actually, my research theorizes the existence of two kinds of mass. The potential and the kinetic mass.

Total mass of particle = potential mass + kinetic mass.

Further the total mass of particle only has a minimum but no maximum value. The property of mass has a lower bound but no upper bound.
 
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Oh, and those are all in the point of view of the more massive one.
 
If there is no disparity of mass (very large and very small), then gravity cannot exist between two objects of equal mass because the forces of push or pull would be exactly equal.
 
No, Rg is A LOT less than G.
 
  • #10
How do we make Rg very large so that we can travel to the star?
 
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