Can rotation wt, lift leverage wt

  • Thread starter Thread starter Newtons-law
  • Start date Start date
  • Tags Tags
    Lift Rotation
AI Thread Summary
The discussion explores the mechanics of a rotating wheel with weights and their potential to create leverage. When a 50 lb weight rotates to the bottom of the wheel, it can exert enough force through a bar attached to the shaft to lift a 15 lb weight on a teeter-totter, provided the moment created by the bar exceeds that of the weight. Additionally, the scenario involving a 10 lb ball rolling down a 45-degree tube raises questions about whether it can cause a sliding motion when it hits a stopping point under 40 lbs of pressure. The mechanics suggest that if the force from the ball's impact is sufficient, it could indeed cause the tube to slide. Overall, the principles of leverage and momentum are central to understanding these scenarios.
Newtons-law
Messages
14
Reaction score
0
Question: On one side of a wheel there is 50 lbs of weight, if the wheel is released the weights would rotate with the wheel until the weights where at the bottom and stop. Let's say this wheel has a shaft in the middle of the wheel that turns as the wheel does, if you put weights on one side of the wheel, when the wheel is released the the wheel and shaft turns until the weights stop at the bottom. Ok on the shaft there is bar welded to it, a long enough bar to use for leverage as the wheel turns {like a fan blade attached to its shaft}. Now let's say we have a balance scale or a teeter totter with 15 lbs at one end. If 50 lbs of weight in rotation on a wheel is pushing down with the attached bar, could the bar push down on the other end of the teeter totter that has no weight and lift the 15 lbs of weight on the other end of the teeter totter?
 
Physics news on Phys.org
Certainly if the bar provides a moment sufficient to exceed the moment applied by the 15 lb weight. Basically shaft through the wheel and the bar behave likd a cam shaft.
 
I'm not completely sure I understand your scenario (a picture would help), but yes, you can use a lever to lift a 15 lb weight with a 50 lb weight.
 
Ok let's say we have a ball weight or round weight of 10 pounds and roll it down a tube or half tube that is 5 ft long and at a 45% slope and at the end of the tube there is a stopping point. The end of the tube or the place where the ball stops is attached only by bearings that slide forward and after 2 inch's a metal lip will stop the forward motion of the small portion of the tube that slides. If there is 40 lbs of pressure an inch wide on top of the tube and the 10 lbs ball hits the end of the tube that can slide forward, {will it slide}.
 
45 degree slope
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top