flyingpig
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Homework Statement
Prove that the geometric series \sum_{n=1}^{\infty} r^n if -1 < r < 1
2. The Solution
s_n = r + r^2 + ... + r^n
rs_n =r^2 + r^3 ... + r^{n+1}
s_n - rs_n = r - r^{n+1}
s_n = \frac{r - r^{n+1}}{1 -r}
For |r|<1
As\;n\to\infty\;,r^{n+1}\to \infty
Therefore
\lim_{n\to\infty}s_n=\frac{r}{1-r}
Q.E.D
Question
The solution is what we took in notes during lecture.
Now here is my question why does \lim_{n\to\infty}s_n=\frac{r}{1-r} answer the proof? How does that prove the geometric series \sum_{n=1}^{\infty} r^n converge?