Can Spacetime Curvature Exist Independently of Mass?

[notknowing]

Einsteins field equations are nonlinear. One could interpret this to mean that curvature is itself the source of curvature (thus not only mass). Would it be possible to find a stationary (non-zero) solution of the (non-linearised) field equations without a mass being present - a kind of spacetime deformation which has an existence independent of mass ?
Has someone proven already that this can not exist ?

 

[FunkyDwarf]

There already is one. Energy as well as mass deform spacetime, not just mass. But no, as far as i know the deformations are not self feeding ie you don't get one spacetime warping causing another. i think.

 

[LURCH]

Is it not the mass of the energy that causes the warping?

NK, although it has been shown (or so I've read) that gravity itself contributes to its own overall strength (BTW, I find this a trully mind-blowing idea!), I also have never heard of any proposed mechanism by which a gravitational field can be its own cause. I think it sounds rather like being one's own Granpa, or a chicken laying the egg from which that same chicken was hatched. Nothing can be its own cause, all "things" must be caused by some other "thing", and AFAIK, gravity needs mass to cause it.

However, this might be a way of describing Black Holes. The mass inside the event horizon is completely and forever (?) cut off from this universe, yet the BH itself continues to have an effect on outside objects through the mechanism of gravity. Could this be described as an instance where the mass of the central object of a gravitational field has "dissappeared" (being that it is no longer exactly "in" our universe), yet the mass of the gravitational field left behind is enough to perpetuate itself?

That doesn't sound right to me, but I'm going to look around a bit and see if I can't find the exact flaw in it.

 

[notknowing]

Is it not the mass of the energy that causes the warping?

NK, although it has been shown (or so I've read) that gravity itself contributes to its own overall strength (BTW, I find this a trully mind-blowing idea!), I also have never heard of any proposed mechanism by which a gravitational field can be its own cause. I think it sounds rather like being one's own Granpa, or a chicken laying the egg from which that same chicken was hatched. Nothing can be its own cause, all "things" must be caused by some other "thing", and AFAIK, gravity needs mass to cause it.

However, this might be a way of describing Black Holes. The mass inside the event horizon is completely and forever (?) cut off from this universe, yet the BH itself continues to have an effect on outside objects through the mechanism of gravity. Could this be described as an instance where the mass of the central object of a gravitational field has "dissappeared" (being that it is no longer exactly "in" our universe), yet the mass of the gravitational field left behind is enough to perpetuate itself?

That doesn't sound right to me, but I'm going to look around a bit and see if I can't find the exact flaw in it.

Hi, Thanks for your comments. I'm not convinced by your chicken and egg argument though. In a propagating wave, one could say that each new cycle is the consequence of the previous one (many chickens and eggs !). In fact, I suspect there exists some kind of soliton like solution to the wave equations , but then of a stationary type. Maybe one could think of it like an eternal vortex in spacetime (no friction or energy dissipation). Maybe that a skilled mathematicion could find such solution. He/she would be famous from day one !

 

[masudr]

Well, the Schwarzschild solution has no stress-energy term.

 

[pervect]

Einsteins field equations are nonlinear. One could interpret this to mean that curvature is itself the source of curvature (thus not only mass). Would it be possible to find a stationary (non-zero) solution of the (non-linearised) field equations without a mass being present - a kind of spacetime deformation which has an existence independent of mass ?
Has someone proven already that this can not exist ?

The stress-energy tensor (T_uv) is the right hand side of Einstein's field equations, G_uv = 8 pi T_uv, i.e. the stress energy tensor causes gravity, not mass.

I'm not quite sure what sort of solution you are looking for, but it is worth noting that gravitational radiation is nothing but "ripples" of curvature.

Thus in an exact solution of Einstein's field equations, gravitational radiation does not appear on the right hand side of Einstein's equations aas a source term.

However, gravitational radiation is a form of energy, so one would expect it to have some effect on space-time curvature.

The resolution of this issue is that gravitational radiation does not have an actual stress-energy tensor, but that the non-linear terms give it an "effective" stress-energy tensor, if instead of taking the exact solution of Einstein's equations you ignore the "ripples" and look for the value of overall curvature, ignoring the ripples.

 

[notknowing]

The stress-energy tensor (T_uv) is the right hand side of Einstein's field equations, G_uv = 8 pi T_uv, i.e. the stress energy tensor causes gravity, not mass.

I'm not quite sure what sort of solution you are looking for, but it is worth noting that gravitational radiation is nothing but "ripples" of curvature.

Thus in an exact solution of Einstein's field equations, gravitational radiation does not appear on the right hand side of Einstein's equations aas a source term.

However, gravitational radiation is a form of energy, so one would expect it to have some effect on space-time curvature.

The resolution of this issue is that gravitational radiation does not have an actual stress-energy tensor, but that the non-linear terms give it an "effective" stress-energy tensor, if instead of taking the exact solution of Einstein's equations you ignore the "ripples" and look for the value of overall curvature, ignoring the ripples.

Indeed, gravitational energy does not have an actual stress-energy tensor, and the non-linear terms indeed behave as an "effective" stress-energy tensor and the energy in the gravitational field can not be localised (though it is non-zero) but that does not mean that we can say with mathematical certainty that such a massless and non-propagating curvature solution can not exist. As long as I haven't seen the proof, I will not be convinced.

 

[lightarrow]

... but it is worth noting that gravitational radiation is nothing but "ripples" of curvature.

Sorry if I introduce a question here. Does it mean that both signs of curvature must exist, and so, both signs of mass as well?

 

[Garth]

Indeed, gravitational energy does not have an actual stress-energy tensor, and the non-linear terms indeed behave as an "effective" stress-energy tensor and the energy in the gravitational field can not be localised (though it is non-zero) but that does not mean that we can say with mathematical certainty that such a massless and non-propagating curvature solution can not exist. As long as I haven't seen the proof, I will not be convinced.

In the standard form of Einstein's field equation:
(why doesn't my Tex work here?)

the gravitational 'energy' does not appear, only that of non-gravitational mass, stress, momentum and energy, which appears on the right hand side of the equation.

All that appears on the left hand side of the equation is the curvature of space-time, which has therefore to include any notion of gravitational energy such as might be transported by gravitational waves. This is one reason why GR is said to be an 'improper energy theorem'.

This is a non-linear equation in which perturbations in space-time might well be "self feeding".

Garth

 

[Thrice]

This question might not even make any sense. "Curvature" is just another name for field strength. You're asking if it's possible to have a field without a source. As far as I know that's a matter of definition. You might as well ask for sentences without words.

 

[pervect]

Indeed, gravitational energy does not have an actual stress-energy tensor, and the non-linear terms indeed behave as an "effective" stress-energy tensor and the energy in the gravitational field can not be localised (though it is non-zero) but that does not mean that we can say with mathematical certainty that such a massless and non-propagating curvature solution can not exist. As long as I haven't seen the proof, I will not be convinced.

I'm not saying that "such a solution" doesn't exist either, but mainly because I'm not really clear on exactly what it is you are looking for.

If you define mass, energy, and momentum as the ADM mass, energy and momentum, we should be able to apply the rules of SR to say that any massless solution must be moving at 'c', for the ADM energy and momentum form a 4-vector with the ADM mass as the invariant of that 4-vector, just as mass of a point particle in SR in the invariant of the energy-momentum 4-vector of that particle.

 

[notknowing]

I'm not saying that "such a solution" doesn't exist either, but mainly because I'm not really clear on exactly what it is you are looking for.

If you define mass, energy, and momentum as the ADM mass, energy and momentum, we should be able to apply the rules of SR to say that any massless solution must be moving at 'c', for the ADM energy and momentum form a 4-vector with the ADM mass as the invariant of that 4-vector, just as mass of a point particle in SR in the invariant of the energy-momentum 4-vector of that particle.

It is not clear to me what you mean with "ADM". However, though the solution I'm looking for has no barionic mass, it does not need to be massless since the gravitational field contains energy (and thus mass). Therefore, the self-feeding-curvature (or "solution") is not massless and can therefore not move at the speed of light.

 

[pervect]

It is not clear to me what you mean with "ADM". However, though the solution I'm looking for has no barionic mass, it does not need to be massless since the gravitational field contains energy (and thus mass). Therefore, the self-feeding-curvature (or "solution") is not massless and can therefore not move at the speed of light.

ADM mass, energy, and momentum are one of the standard ways to measure the mass, energy, and momentum of a composite system in standard General relativity. Certain conditions have to be met, which I'll go into later.

The name is taken from the intials of Arowitt, Deser and Misner, who first published it as a notion of the total energy and momentum contained in a spatial hyperslice, computed by means of a Hamiltonian formulation. You can find the details in Wald's "General Relativity", and probably a lot of other GR textbooks.

The concept is applicable to any asymptotically flat space-time. Asymptotic flatness of a space-time is an automatic consequence if you have a source region of space-time with a non-zero stress-energy tensor surrounded by an infinite vacuum region. (Note that our universe doesn't qualify as asymptotically flat, at least in the standard cosmological models such as the FRW (Friedman, Walker, Robertson) models.)

You can think of the ADM mass, energy, and momentum as arising from Noether's theorem, arising from space and time translations "at infinity", more precisely at "spatial infinity", in the region where space-time is "almost" flat. Space translations give the conserved total momentum via Noether's theorem, time translations give the conserved total energy. The result transforms like a 4-vector. This means that objects with zero ADM mass must move at 'c' as a whole, as measured in the nearly Minkowskian nearly flat region "at infinity".

 

[notknowing]

ADM mass, energy, and momentum are one of the standard ways to measure the mass, energy, and momentum of a composite system in standard General relativity. Certain conditions have to be met, which I'll go into later.

The name is taken from the intials of Arowitt, Deser and Misner, who first published it as a notion of the total energy and momentum contained in a spatial hyperslice, computed by means of a Hamiltonian formulation. You can find the details in Wald's "General Relativity", and probably a lot of other GR textbooks.

Thanks for this clarification. I found it back now in Gravitation by Misner, Thorne and Wheeler.
The solution I'm looking for corresponds to a rotating "disk" of spacetime. So, it does not have spherical symmetry, but it has axial symmetry (and a plane of symmetry). A very rough indication of how this can exist is the following: The gravitational field contains energy and should therefore have a tendency to contract itself (or collapse). If it has angular momentum one could have a kind of centrifugal force which balances exactly this contraction tendency such that one obtains a stable solution.
I know that this very rough and uses an analogon from classical physics which is not valid here. I just mention it to make it a little bit more plausible to the sceptics.
I am convinced that such a solution exists but I realize that I have not the mathematical skills to find it. It would be wonderfull if someone in this forum could find it. Maybe it requires a genius like Schwarzschild to find it.

 

[pervect]

The only thing I've seen which might be helpful is a weak-field analysis of a ring laser by Mallett.

http://www.physics.uconn.edu/~mallett/Mallett2000.pdf

Mallett has a strong field analysis of a cylinder of light, but it has been criticised in the literature and I personally agree with the criticisms.

http://www.arxiv.org/abs/gr-qc/0410078

I'm not aware of any problems with the Mallett's weak-field analysis, though I have some concerns about the beam profiles

Finding a beam profile solution that obeys Maxwell's equations is trickier than it seems - see some of the discussion about Gaussian beams on PF, there was another beam profile that looked promising (think it was a Bessell or non-diffractive beam profile, I'm not sure anymore).

I'm not sure what the equivalent of satisfying Maxwell's equations is for gravity wave beams offhand.

You can probably sidestep some of the beam profile issues if you imagine that the field is being created by massive particles moving very close to c so that their invariant mass * c^2 is much less than their energy, but this gets you a step away from your original idea.

 

[notknowing]

The only thing I've seen which might be helpful is a weak-field analysis of a ring laser by Mallett.

http://www.physics.uconn.edu/~mallett/Mallett2000.pdf

Mallett has a strong field analysis of a cylinder of light, but it has been criticised in the literature and I personally agree with the criticisms.

http://www.arxiv.org/abs/gr-qc/0410078

I'm not aware of any problems with the Mallett's weak-field analysis, though I have some concerns about the beam profiles

Finding a beam profile solution that obeys Maxwell's equations is trickier than it seems - see some of the discussion about Gaussian beams on PF, there was another beam profile that looked promising (think it was a Bessell or non-diffractive beam profile, I'm not sure anymore).

I'm not sure what the equivalent of satisfying Maxwell's equations is for gravity wave beams offhand.

You can probably sidestep some of the beam profile issues if you imagine that the field is being created by massive particles moving very close to c so that their invariant mass * c^2 is much less than their energy, but this gets you a step away from your original idea.

Thanks Pervect for these interesting links. Still, it would be nice if someone at least could give it a try (original idea) ...

 

[Garth]

Thanks Pervect for these interesting links. Still, it would be nice if someone at least could give it a try (original idea) ...

Okay, try the Einstein-Rosen Bridge, otherwise known as a Lorentzian wormhole.

Such a wormhole might be formed inside a rotating, or Kerr, Black Hole.

Imagine a spinning collapsing massive star core after the star itself had gone super-nova. About 3 or more solar masses dissappear into the ring singularity at its centre. You try to follow the mass inside the (now double) event horizon and instead of coming up against the massive singularity you reappear in another part of the universe, or in a different universe! Where has the mass gone?

Although such a bridge is unstable it may be stabilised by a sphere of large amount on negative pressure exotic matter (DE??). You would then have a black hole in this universe and one in possibly another universe but the mass is nowhere to be seen!

Garth

 

[pervect]

The picture I get is more of the photon sphere around a black hole. (This isn't a stable orbit, unfortunately).

Now we get rid of the black hole, and replace it with only a ring of light. Can we use the gravity field of the ring of light itself to eliminate the black hole?

Light beams going in opposite directions attract. (I've got a reference for this somewhere). So the idea is to use the gravitational interaction of the circulating light itself to keep the light in its circular orbit.

My intiution says that it wouldn't be stable, and that the light would have to have to be a perfect ring with a zero area delta-function cross section. If you give the light a finite cross section, I don't think it will work.

Working it out in terms of a metric is beyond me - working it out in the linearized approximation in more detail would be a challenge, but with the Mallett paper as a guide I think it would be possible, but quite time consuming and very involved. (It wouldn't be terribly involved if one trusted Mallett implicitly, but if one really wanted to understand every step and check for errors it would take considerable effort.)

The next step is to replace the light with a gravity wave.

A simplification in the opposite direciton would be to replace the light / gravity waves with a beam of particles of non-zero rest mass, but ultra-relativistic in energy. One can then understand the gravitational interaction a bit more intuitively. Gravitomagnetic effects will be quite significant. Gravitomagnetism explains why two parallel light beams attract each other if they are going in opposite directions, and don't attract each other if they are going in the same direction.

 

[MeJennifer]

The picture I get is more of the photon sphere around a black hole. (This isn't a stable orbit, unfortunately).

But are there any stable orbits in GR?
I thought that was not the case.

 

[pervect]

Sure there are. Take a look at http://www.fourmilab.ch/gravitation/orbits/ for instance, look for the term "stability". It's easiet to talk about this in the context of circular orbits, which don't have to worry about the precession issues that elliptical orbits have.

Circular orbits are stable when there is a minimum in the effective potential.

Try for instance, setting L=3.47 in the simulator. You'll see a green line at the minimum of the effective potential. This indicates a stable circular orbit. Click on the effective potential diagram near the green line -you'll launch the simulator generating the stable orbit (it will be exactly circular only if you click right on the green line).

Now reduce L to 3.46. There will no longer be any minimum of the effective potential, thus there are no stable circular orbits. If you read the detailed derivation you'll see that L=sqrt(12) is the critical point which generated this transistion.

 

[pess5]

Einsteins field equations are nonlinear. One could interpret this to mean that curvature is itself the source of curvature (thus not only mass). Would it be possible to find a stationary (non-zero) solution of the (non-linearised) field equations without a mass being present - a kind of spacetime deformation which has an existence independent of mass ?
Has someone proven already that this can not exist ?

I'm pretty sure there is a soln to Einstein's field eqns for a massless universe which contains only energy. In fact, this is what BB cosmology is based upon. Alan Guth, the inventor of the Rapid Inflation Theory, and the Everything From Nothing theory, theorizes that quantum gravity flutuations gave rise to the BB event. That these fluctuations are normal in the preBang realm. If they superimpose just right, a false vacuum forms which becomes unstable and inflates creating space & time, then cooling allows for particle crystalization and matter-based gravity wells.

The quantum gravity fluctuations in the preBang realm are just that ... gravity-like variations within the medium. So energy exists in the absence of rest mass. However, with no material entity in existence, location in space & time have little meaning (no distict reference) far as how we percieve it in the postBang. Yet, gravity-like fluctuations are CHANGE, and that assumes some form of time and space.

That said, I have heard that Einstein's GR has a soln for a massless universe, ie energy alone. This is consistent with Guth's false vacuum theory.

pess

 

[MeJennifer]

Sure there are. Take a look at http://www.fourmilab.ch/gravitation/orbits/ for instance, look for the term "stability". It's easiet to talk about this in the context of circular orbits, which don't have to worry about the precession issues that elliptical orbits have.

Circular orbits are stable when there is a minimum in the effective potential.

Try for instance, setting L=3.47 in the simulator. You'll see a green line at the minimum of the effective potential. This indicates a stable circular orbit. Click on the effective potential diagram near the green line -you'll launch the simulator generating the stable orbit (it will be exactly circular only if you click right on the green line).

Now reduce L to 3.46. There will no longer be any minimum of the effective potential, thus there are no stable circular orbits. If you read the detailed derivation you'll see that L=sqrt(12) is the critical point which generated this transistion.

So when is an orbit stable and when not in GR?
I thought that an object in orbit is unstable and spirals in because of the loss of energy due to gravitational waves. Are there orbits for which this is not the case?

 

[pervect]

The defintion of stability that I'm using (and that the webpage I cited is using) is similar to the one used to define the stability (or lack therof) of the Lagrange points, regarding the behavior of the orbits when small pertubations are made in the inital conditions.

The analysis on the webpage does not include gravitational radiation. However I don't think the situation of a rotating perfect ring has any quadropole moment. And quadropole moment is required to have a source of gravitational radiation. So I think gravitational radiation would be highly surpressed from a rotating ring. It would be a very tiny effect in any event - and it would tend to be supressed even further by the symmetry of the system. Small imperfections in the ring would still radiate, so there would be some gravitational radiation, but it would be very small (ideally zero, one would need information about the imperfections to determine more).

Circular orbits make the analysis of stability easy, because one can plot the behavior of r vs t in one dimension as the only interesting part of the behavior.

Unstable orbits act like a pin balanced on its point. They depart very quickly away from the equilibrium point. So the equilibrium point is an exact solution of the orbital equations for an unstable orbit, but if you depart even slightly from the correct initial conditions, your object will quickly spiral outwards or inwards, with some exponential time constant.

You can see this behavior on the simulator. You can also see this from examining the graph of effective potential. If the object is in a valley, it has the same equations of motion for r vs time that a ball trapped in a valley has. The ball is trapped by the valley walls, and the orbit (and the position of the ball) are said to be stable.

If the ball is on the top of a hill, though, it is unstable. The slightest push sends the ball off to one side or the other. The same thing is true for the orbit. A small error in initial conditions will send the object (or, in the original case, light beam) either out to infinity, or spiraling into the black hole. It takes some sort of active control system to stabilize an unstable system.

Formally, stability (in the sense I'm using it) is determined by finding the eignevalues of the linearized system. If those eignevalues all have positve real parts, the exponential response of the system is damped, and the system is stable. If those eignevalues have negative real parts, small errors in initial conditions grow exponentially, leading to active instability. Zero eigenvalues represent marginal stability. In terms of a "ball on a surface" analysis, a zero real part describes a ball on a flat plane. It doesn't "fall off" the top of a hill, but neither is there any restoring force as there would be if the ball was in a valley.

 

[MeJennifer]

So I take it between all the flowery language that the answer is yes orbits in GR are not stable, while the effect is very smalll, orbits spiral towards the center.

How is it goinig to help anyone understand GR if we cannot get a simple yes/no answer on this.

I really do not see how flowery language is going to help here.
So what if you use another definition of stability or that the given website does not handle this, or that the effect is small anyway?

The fact that orbits are not stable in GR is profound and interesting for anyone to understand GR.

 

[masudr]

Well, what if there are no quadropole moments?

 

[pervect]

So I take it between all the flowery language that the answer is yes orbits in GR are not stable, while the effect is very smalll, orbits spiral towards the center.

How is it goinig to help anyone understand GR if we cannot get a simple yes/no answer on this.

I really do not see how flowery language is going to help here.
So what if you use another definition of stability or that the given website does not handle this, or that the effect is small anyway?

The fact that orbits are not stable in GR is profound and interesting for anyone to understand GR.

Actually, I'm trying to keep it reasonably simple and still explain to you the more-or-less standard defintion of "stable orbit".

Meanwhile, you are adopting your own non-standard defintions. While I suppose I could adopt your defintions for the purpose of conseversation, this might a) confuse other people and cause arguments and b) would not help you understand standard written material, such as the web page I quoted, which also talked about the stability of circular orbits in GR.

You will frequently see statements in the literature and textbooks that say, for example "The last stable circular orbit around a black hole is at r=6GM/c^2, orbits inside this radius are unstable". This is using a standard defintion of stability, which I tried to explain, and which has absolutely nothing to do with the gravitational radiation issue you are concerned about.

 

[pmb_phy]

So I take it between all the flowery language that the answer is yes orbits in GR are not stable, while the effect is very smalll, orbits spiral towards the center.

I'm comming in late to this conversation but I assume that the reason for your answer has to do with gravitational energy being radiated as the Earth revolves around the sun. Is that true?

I really do not see how flowery language is going to help here.

Yeah. I hate it when that happens too.

Best wishes

Pete

 

[MeJennifer]

I'm comming in late to this conversation but I assume that the reason for your answer has to do with gravitational energy being radiated as the Earth revolves around the sun. Is that true?

Actually I like to know in general.

It is my understanding of GR that an object in orbit will generate gravitational waves, which will cause the spiraling in of such an object. I understand the effect is small, but that is no argument for saying that orbits in GR are stable. GR effects compared to Newtonian physics are small as well, should that be a reason to tell people there are no relativistic effects?

So to come back to the issue, would there be any difference between an orbit around a black hole, both outside and inside the event horizon compared to an orbit of say the Earth around the sun with regards to gravitational waves and thus stability?

Actually, I'm trying to keep it reasonably simple and still explain to you the more-or-less standard definition of "stable orbit".

Meanwhile, you are adopting your own non-standard definitions. While I suppose I could adopt your definitions for the purpose of conversation, this might a) confuse other people and cause arguments and b) would not help you understand standard written material, such as the web page I quoted, which also talked about the stability of circular orbits in GR.

You will frequently see statements in the literature and textbooks that say, for example "The last stable circular orbit around a black hole is at r=6GM/c^2, orbits inside this radius are unstable". This is using a standard definition of stability, which I tried to explain, and which has absolutely nothing to do with the gravitational radiation issue you are concerned about.

The whole point is pervect that when I asked you:

"I thought that an object in orbit is unstable and spirals in because of the loss of energy due to gravitational waves. Are there orbits for which this is not the case?"

You could have simply acknowledged or rejected that gravitational waves cause orbits to collapse instead of questioning my understanding of what stable means.
I understand the effect is very small, but compared to Newtonian physics GR effects are very small as well, by analogy would that be a reason to keep people away from understanding GR?

 

[Stingray]

You could have simply acknowledged or rejected that gravitational waves cause orbits to collapse instead of questioning my understanding of what stable means.
I understand the effect is very small, but compared to Newtonian physics GR effects are very small as well, by analogy would that be a reason to keep people away from understanding GR?

First of all, it's clear that you still don't understand what orbital stability means. It has nothing to do with the periodicity of the orbit or the amount of energy loss. You might want to reread pervect's post.

Anyway, it is true that orbits decay in GR due to gravitational wave emission. The effect goes to zero, however, if one mass is very small. But certain circular orbits remain unstable (in the standard definition of that word) even in that limit.

 

[MeJennifer]

Anyway, it is true that orbits decay in GR due to gravitational wave emission. The effect goes to zero, however, if one mass is very small.

Good that is all what I was asking, thankg for giving me a straight forward answer!

First of all, it's clear that you still don't understand what orbital stability means.

So a decaying orbit would still be considered a stable orbit by people who unlike me understand?

 

[Stingray]

So a decaying orbit would still be considered a stable orbit by people who unlike me understand?

Yes, usually. But the meaning of these concepts becomes unclear if the orbit is decaying very quickly.

 

[Chris Hillman]

Geons, anyone?

Hi again, notknowing,

Einsteins field equations are nonlinear. One could interpret this to mean that curvature is itself the source of curvature (thus not only mass). Would it be possible to find a stationary (non-zero) solution of the (non-linearised) field equations without a mass being present - a kind of spacetime deformation which has an existence independent of mass ?

It sounds very much like you want to notion of a "geon", which was introduced by Wheeler under the slogan "mass without mass". Try these: http://arxiv.org/find/gr-qc/1/OR+ti:+geons+ti:+geon/0/1/0/all/0/1
(I should caution that some of these papers make controversial assertions. Note too that there are various ways to define "mass" which may be more or less appropriate in different circumstances.)

I'm pretty sure there is a soln to Einstein's field eqns for a massless universe which contains only energy.

This probably is not what you want (nothing to do with "inflation"--- by the way, I think you meant "preBB cosmology"), but there are many nontrivial exact vacuum solutions which have zero ADM mass. A large family of them was found by Papapetrou (this is a subfamily of the Ernst vacuums, the family of all stationary axisymmetric vacuum solutions to the EFE), but most of these are not asymptotically flat. A simple AF example has been discussed by Bonnor.

The issue of interpretation is often vexed in gtr, and it is not clear that these solutions are valid. In weak-field gtr, the two halves of the Ernst equation decouple, which means that you can treat sources have independently variable mass-energy density and momentum density. That is, in Newtonian gravitation, a spinning disk and a nonspinning disk (with uniform density and the same mass) give the same gravitational field, but in gtr the fields differ (the differences arise from a zero or nonzero gravitomagnetic field). But you would presmably not want to allow a source which has nonzero angular momentum but zero mass! If I recall correctly, the massless AF Bonnor vacuum does have zero Komar mass but nonzero Komar angular momentum. (I am too lazy to check this right now.)

Well, what if there are no quadropole moments?

masudr, I am coming into this rather late, but I guess that you meant: do systems with constant mass, angular momentum, and quadrupole moment but with time varying octupole moments (next higher order after quadrupole moments) produced gravitational radiation, according to the linearized-EFE? The answer is yes. (More pedantically, we can define moments for mass-energy and momentum of all orders, so that in addition to "mass-quadrupole moment" and so on, we can compute a "current-quadrupole moment" which gives another contribution to the radiation, and so on for higher orders.)

So I take it between all the flowery language that the answer is yes orbits in GR are not stable, while the effect is very smalll, orbits spiral towards the center.?

Oh dear, Jennifer, I can't imagine how you might have been led to that conclusion, but be assured that it is not true! I agree with stingray and pervect that you appear to have confused closed or decaying orbits with stable orbits-- that's unfortunate, but probably not your fault (probably you were reading something which didn't bother to use the correct terms, or to note that these are distinct concepts?)

The standard definition of stable, as used in dynamical systems theory and in applications in gtr, e.g. to test particle orbits, basically means that the orbit is stable under small perturbations in the sense that small changes don't change the orbit drastically. It does NOT contradict either quasi-Keplerian motion (so that the orbits are not closed) or inspiral (aka orbital decay) due to gravitational radiation carrying away energy from the system.

Chris Hillman

 

[notknowing]

Hi again, notknowing,



It sounds very much like you want to notion of a "geon", which was introduced by Wheeler under the slogan "mass without mass". Try these: http://arxiv.org/find/gr-qc/1/OR+ti:+geons+ti:+geon/0/1/0/all/0/1
(I should caution that some of these papers make controversial assertions. Note too that there are various ways to define "mass" which may be more or less appropriate in different circumstances.)

Hi, indeed the concept of a "geon" is what I had in mind. I quickly looked through some of the references (on arxiv) you gave and it seems I have a lot of reading to do. I had never heard of a "geon" before, and probably most members in this forum neither (as no one else pointed me to this). It seems to indicate that intuition is worth something in physics .
Form the quick look I had at some of the articles, it seems that they are working with solutions of the linearized equations, but this is not what I had in mind. I think that the fully nonlinear equations allow for much more interesting (soliton-like) solutions, though they are probably very hard to solve. Suppose for a moment that such stable solutions indeed exist, then they could probably be of relevance to the "missing mass" problem.

 

[Chris Hillman]

Vacuum solutions with vanishing ADM mass

I wrote a lengthy comment on this thread the other day, but unfortunately due to system instability at PF I lost my work. So I'll keep this brief, at least until the system becomes more stable.

The original poster may or may not be interested in solutions answering to the description in the title, but Papapetrou discovered a large class of massless stationary axisymmetric vacuum solutions, which is of course a subclass of the Ernst vacuums (the class of all stationary axisymmetric vacuum solutions). The Papapetrou vacuums are in general not asymptotically flat, but Bonnor gave a simple example of a nontrivial asymptotically flat stationary axisymmetric Ernst vacuum with vanishing ADM mass.

The issue immediately arises of what could cause such behavior. That is, what might be the source of such a gravitational field? In particular, what kind of isolated, compact configuration of moving matter might produce an asymptotically flat stationary axisymmetric field with zero mass?

As it happens, in weak-field gtr, the field equations for stationary axisymmetric vacuums reduce to two uncoupled equations whose source is respectively mass-energy and (angular) momentum.

Imagine an isolated thin uniform density disk. In Newtonian gravitation, because of the axial symmetry of the source, a spining or nonspinning disk will produce identical gravitational fields. In gtr, spinning up the disk so that the rim is moving at nonrelativistic velocities will in principle produce a small gravitomagnetic field, so in gtr, in principle a physicist orbiting a massive disk can in principle tell whether or not it is spinning by testing within his spaceship/laboratory for possible gravitatomagnetic effects on test particle motion.

(Non-relativistic: spinning up the disk will eventually increase the effective mass-energy density inside the disk. The additional energy has of course come from whatever physical process we are using to spin up the disk--- which we profoundly desire to avoid modeling! This last brings up the difficulty of devising thought experiments, due to the fact that all forms of mass-energy gravitate, which can create problems when you wish to make something change without modeling exactly how the necessary energy is provided. Compare say Born's thought experiment in which some non-EM force is used to uniformly accelerate two identical charged particles away from each other. If you try to construct the analogous gravitational experiment, you are liable to wind up postulating infinitely strong yet massless strings pulling on the two particles! But such massless strings are sufficiently unphysical to possibly destroy the value of the idealization.)

A physically reasonable source presumably shouldn't have angular momentum without mass. But at least in weak-field gtr, it seems that the field equation does not rule out this possibility. Such overgenerosity is perhaps analogous to the fact that neither Newton's field equation (the Laplace equation, in the classical field theory reformulation of Newtonian gravitation) nor the EFE rule out sources which possesses negative mass.

Anyway, my point is that these considerations suggest that these solutions may be artifacts of using inappropriate boundary conditions.

Chris Hillman