B Can the output forces for F3 and F4 be the same as F2 in hydraulic lifting?

AI Thread Summary
The discussion centers on calculating output forces F3 and F4 in a hydraulic lifting system, where input force F1 and area A1 are consistent across three cases. According to Pascal's principle, output force F2 is determined by the formula F2 = A2/A1 x F1. It is noted that forces acting on the top surfaces of areas A2 in cases 2 and 3 do not contribute to movement, thus producing no mechanical work. The conversation emphasizes the importance of considering only the "moving areas" for calculating net forces. The thread was ultimately locked and suggested for relocation to a more appropriate forum for homework help.
ucody0911
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User has been reminded to post schoolwork problems in the Homework Help forums and to always show their Attempt at the Solution
Hello All,
pls see picture , input force F1 and area A1 and second area A2 are all same for 3 cases
for the 1st case , output force F2 should be F2=A2/A1 x F1 , by pascal's principle ,
what about output forces of F3 and F4 ? can be same as F2 ? how i calculate them ?

thanks
 

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Hydraulic pressure applies on all the inner surfaces, upper, base and the sides of A2. Some forces by pressure cancel because they have opposite directions and you would get the net results.
 
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The "moving areas" are the only ones to be considered.
The force on the top surfaces A2 of cases 2 and 3 produces no movement; therefore, no mechanical work.
 
Lnewqban said:
The "moving areas" are the only ones to be considered.
The force on the top surfaces A2 of cases 2 and 3 produces no movement; therefore, no mechanical work.
Presumably the red open outline represents a free-to-move piston. Why wouldn't the piston move?
 
Last edited:
ucody0911 said:
Hello All,
pls see picture , input force F1 and area A1 and second area A2 are all same for 3 cases
for the 1st case , output force F2 should be F2=A2/A1 x F1 , by pascal's principle ,
what about output forces of F3 and F4 ? can be same as F2 ? how i calculate them ?

thanks

Please re-post this in the Homework Help, Introductory Physics forum and use the hints you have been given here to show your work toward a solution. This misplaced schoolwork thread is now locked.
 
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
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