Can the polarity at the 2 ends of a solenoid be the same in normal conditions?

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In the discussion about the polarity of a solenoid, it is questioned whether both ends can be South poles under normal conditions. The Clock rule mentioned is not recognized in standard physics, leading to confusion. Participants agree that if both ends are identified as South poles, it raises the question of where the North pole is located. It is clarified that the North pole is typically found along the top portion of the solenoid's core. The conversation emphasizes the importance of understanding magnetic polarity in solenoids.
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Homework Statement
I encountered the following question but by using Clock rule, both the ends are coming out to be South poles. Is this possible? If not, then what will be the polarity at both ends?
Relevant Equations
None
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MadMax_8228 said:
Homework Statement: I encountered the following question but by using Clock rule, both the ends are coming out to be South poles. Is this possible? If not, then what will be the polarity at both ends?
Relevant Equations: None

View attachment 340132
Yes. I don't recall ever hearing of such a Clock rule in physics. I do agree with you that both A and B are South magnetic poles.

Where is the North Pole or Poles? Along the top portion of solenoid's core.
 
Thread 'Chain falling out of a horizontal tube onto a table'

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
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