Can the Schrondinger Wave Equation Be Used to Solve Normalized Cases?

vick5821
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Homework Statement



Solving Normalized case of schrondinger wave equation

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The Attempt at a Solution



This type of question is not normalized case of solving using schrondiger equation. Any example of solving normalized case using schrondinger equation ? How would it be ? Using same formula and same way of solving ?

Thank you
 

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The Schrodinger equation is a linear equation, so if ##\psi## is a solution, any constant multiple of it will also be a solution. When normalize the solution, you're simply requiring that the constant be chosen such that
$$\int \psi^*\psi\,dx = 1.$$
 
Yes. I am aware about that. Just that I wanted some example problem solving on how to solve for normalize case and how would the question asked ?

Thank you
 
What do you mean by "solve for normalize case"? I suggest you look up the infinite square well in your textbook. That's probably the simplest example.
 
As attached, the wave equation given is not normalized case and we solve it using Not Normalized method. I want to ask how would it be if the wave equation given is in NORMALISED form and how to solve it ?

Thank you
 
What you're saying doesn't make sense. There is no such thing as a normalized case of the wave equation. You have the wave equation. You find solutions. You normalize the solutions. That's it.
 
Initially, I get the wave equation , then I try to do see whether the wave equation is normalized or not by see this condition :
If
<refer attachment>

then the wave equation is normalized.

If it is not, means the wave equation is not NORMALIZED
 

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The (time-independent) wave equation is
$$-\frac{\hbar^2}{2m}\frac{d^2}{dx^2}\psi + V(x)\psi = E\psi.$$ ##\psi## is a solution to the wave equation.

Take a look at http://physicspages.com/2011/01/26/the-infinite-square-well-particle-in-a-box/.
 
Have you refer to the very first attachment ? It is given the solution of the wave equation already. But we have to find the momentum in x and y
 
  • #10
vela said:
The (time-independent) wave equation is
$$-\frac{\hbar^2}{2m}\frac{d^2}{dx^2}\psi + V(x)\psi = E\psi.$$ ##\psi## is a solution to the wave equation.



Any similar question ?
 

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