Can this algebraic integral be solved using trigonometric substitutions?

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SUMMARY

The integral \(\int \dfrac{x+2}{\sqrt{(x-2)(x-3)}} dx\) presents challenges that cannot be simplified through trigonometric substitutions. Attempts to use substitutions such as \((x-2) = t^2\) or \(x = 1/t\) have proven ineffective. A successful approach involves rewriting the integral as \(\frac{1}{2} \int \dfrac{2x-5}{\sqrt{x^2-5x+6}} dx + \frac{9}{2}\int \dfrac{1}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}} dx\), which allows for easier integration of the resulting terms.

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utkarshakash
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Homework Statement


[itex]\int \dfrac{x+2}{\sqrt{(x-2)(x-3)}} dx[/itex]

The Attempt at a Solution



I've tried substitutions like assuming (x-2) = t^2 or x= 1/t or x=1/t^2, but none of them seems to ease the problem. Breaking the integral into two helps to integrate the second but first integral still remains complicated. I'm also sure that trig substitutions won't work here.
 
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utkarshakash said:

Homework Statement


[itex]\int \dfrac{x+2}{\sqrt{(x-2)(x-3)}} dx[/itex]

The Attempt at a Solution



I've tried substitutions like assuming (x-2) = t^2 or x= 1/t or x=1/t^2, but none of them seems to ease the problem. Breaking the integral into two helps to integrate the second but first integral still remains complicated. I'm also sure that trig substitutions won't work here.

Rewrite the given integral as [itex]\frac{1}{2} \int \dfrac{2x-5}{\sqrt{x^2-5x+6}} dx[/itex] + [itex]\frac{9}{2}\int \dfrac{1}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}} dx[/itex]

I hope the two integrals are easy to handle .
 

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