No. Having done the calculation I recommended, I see there is no such discrepancy. For circular motion, there is asymmetry - at all times, A thinks B's clock is slower, and B thinks A's clock is faster.Lets consider a simpler constant velocity scenario. Let us say we have observer A on top of a huge tower of height r and observer B is orbiting at near light speed relative to A at radius R. As B passes A they would both agree the other's clock is running slower. When B completes an orbit both will agree less total time has passed on B's clock. Agree?
You can model it this way, but such arguments are tricky. Certainly it justifies the lack of symmetry.Secondly, if something was orbiting at near light speed, the centripetal forces would be enormous and there would be an additional time dilation effect on B similar to gravitational time dilation due to the equivalence principle. Agree?
The time dilation of particle in accelerator can be computed purely based on its speed, but the effect is asymmetric. The lab thinks the particle's time is slow; the particle thinks the lab's time is fast.P.S. I might be wrong on that last one. I seem to recall an experiment that demonstrated that the time dilation of a particle in a cyclotron is purely a factor of its relative speed and completely independent of the acceleration. Hmmmm. Was it that you could attribute the time dilation to either speed or equivalent gravity but not both?
Anyway, any equivalent gravitational time dilation would not be reciprocal.