Can You Find the Convergent Value of α for this Improper Integral?

wolski888
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EDIT: I am sorry if you can't understand the integral straight away, I am not familiar with using the notion provided by this forum. I tried, but...

Homework Statement


Find all values of the constant α for which the integral:
∫ [(x/(x^2 + 1)) - (3a/(3x + 1))] dx (from 0 to +infinitity)
converges. Evaluate the integral for these values of α (as a function of α).

The Attempt at a Solution


I don't really know how to approach this. It seems simpler to separate it into 2 separate integrals. And in the integral with the constant 'a', I can sub u = 3x + 1, then du = 3dx
Making it: adu/x

I don't really know if I am on the right track.

Thanks for reading this!
Mike
 
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You probably mean adu/u for your substitution. You are started on the right track. Work out both integrals and get the antiderivative as a function of x. Once you get that start working on what the limit of it is as x->infinity. Using the rules of logs will help.
 
Yes, adu/u. My fault. And thanks!
 
OK, now I am confused. The ln|3x+1| as x goes to infinity is infinity. So it diverges. But how do I make it converge? Same with the first part of the integral...
 
wolski888 said:
OK, now I am confused. The ln|3x+1| as x goes to infinity is infinity. So it diverges. But how do I make it converge? Same with the first part of the integral...

Combine the two integral expressions. Use rules of logs. For a special value of a the divergences might cancel.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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