Can You Find the Greatest Value Using Only AM-GM Inequality?

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The discussion centers on maximizing the expression x^3y^4 under the constraint 2x + 3y = 7, with x and y being non-negative. Participants suggest using the AM-GM inequality to derive a solution, proposing to express the variables in a way that allows applying the inequality effectively. A suggestion is made to graph the linear equation in the first quadrant and substitute one variable to simplify the problem. Additionally, the Lagrange multiplier method is mentioned as an alternative approach, although the original poster seeks a solution strictly using AM-GM. The conversation highlights the importance of understanding different mathematical methods while focusing on the specific constraint of the problem.
utkarshakash
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Homework Statement


Find the greatest value of x^3y^4 if 2x+3y=7 and x>=0,y>=0

Homework Equations



The Attempt at a Solution


Let the 7 numbers be (x/3) 3 times and (y/4) 4 times
Using AM GM inequality
<br /> \dfrac{ 3.\frac{x}{3} + 4.\frac{y}{4}}{7} \geq \left[ \left( \frac{x}{3}\right)^3 . \left( \frac{y}{4}\right)^4\right]^{1/7} \\<br /> \left( \dfrac{x+y}{7} \right)^7 \times 3^3.4^4 \geq x^3y^4<br />
But I'm stuck here :(
 
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utkarshakash said:

Homework Statement


Find the greatest value of x^3y^4 if 2x+3y=7 and x>=0,y>=0

Homework Equations



The Attempt at a Solution


Let the 7 numbers be (x/3) 3 times and (y/4) 4 times
Using AM GM inequality
<br /> \dfrac{ 3.\frac{x}{3} + 4.\frac{y}{4}}{7} \geq \left[ \left( \frac{x}{3}\right)^3 . \left( \frac{y}{4}\right)^4\right]^{1/7} \\<br /> \left( \dfrac{x+y}{7} \right)^7 \times 3^3.4^4 \geq x^3y^4<br />
But I'm stuck here :(
It's not clear in your problem statement, but I believe the restriction of x ≥ 0, y ≥ 0 applies to the linear equation, 2x + 3y = 7.

Sketch a graph of the portion of this line that lies in the first quadrant. Then solve this equation for one of its variables to substitute into x3y4 to make this a function of one variable.
 
Mark44 said:
It's not clear in your problem statement, but I believe the restriction of x ≥ 0, y ≥ 0 applies to the linear equation, 2x + 3y = 7.

Sketch a graph of the portion of this line that lies in the first quadrant. Then solve this equation for one of its variables to substitute into x3y4 to make this a function of one variable.

Alternatively, you can use the Lagrange multiplier method. Or, you can recognize this as a so-called "Geometric Programming Problem" and use methods devised for those types of problems.

RGV
 
Ray Vickson said:
Alternatively, you can use the Lagrange multiplier method. Or, you can recognize this as a so-called "Geometric Programming Problem" and use methods devised for those types of problems.

RGV

Thanks. It solved my problem. Though I did not know Lagrange multiplier method but a little GOOGLing around helped me learn this method. But I'm required to solve this using only the A.M. G.M. inequality. Btw thanks for introducing this method to me. It will be really helpful in solving complicated problems.:smile:
 
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