Can you me with this thevenin problem ?

  • Thread starter Thread starter ujnikm
  • Start date Start date
  • Tags Tags
    Thevenin
AI Thread Summary
The discussion revolves around solving a Thevenin problem where the user calculates Rth as 3.667 KΩ and finds Vth1 to be -3.333 V after applying superposition. The user calculates Vth2 as 25 V but receives conflicting information from others suggesting Vth2 could be 30 V. Participants emphasize the importance of showing the work for calculating Vth2 and remind that terminals A-B should be treated as an open circuit during this process. The conversation highlights the need for clarity in calculations to resolve discrepancies in Thevenin voltage values.
ujnikm
Messages
2
Reaction score
0
Can you please help me with this thevenin problem ?

Please guys can you help me with this??
http://forum.allaboutcircuits.com/cache.php?url=http://s14.postimage.org/9eysbodr5/image.png
I set all sources to 0 so we have Rth=3.667 KΩ
then using superposition and remove the current source and replace it with open circuit so we have Vth1 =-3.333 V
then remove the voltage source and replace it with short circuit so we have Vth2=25 V
so Vth=25-3.3333=21.667 V

other friends tell me that Vth2=30 V

what's the correct ??
 
Last edited by a moderator:
Physics news on Phys.org


ujnikm said:
Please guys can you help me with this??
http://forum.allaboutcircuits.com/cache.php?url=http://s14.postimage.org/9eysbodr5/image.png
I set all sources to 0 so we have Rth=3.667 KΩ
then using superposition and remove the current source and replace it with open circuit so we have Vth1 =-3.333 V
then remove the voltage source and replace it with short circuit so we have Vth2=25 V
so Vth=25-3.3333=21.667 V

other friends tell me that Vth2=30 V

what's the correct ??

Listen to your friends :wink:
 
Last edited by a moderator:


gneill said:
Listen to your friends :wink:

why?
 


ujnikm said:
why?

Show your work for finding Vth2. Remember that terminals A-B are an open circuit when finding the Thevenin voltage.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top