Can You Quantify the Upward Force of a Rising Boat on an Incoming Tide?

  • Thread starter Thread starter ckrizan
  • Start date Start date
  • Tags Tags
    Boat Force
AI Thread Summary
To quantify the upward force of a boat rising on an incoming tide, one must consider the weight of the water displaced by the boat. For a 24-foot by 8-foot boat weighing 4,000 lbs, the upward force can be estimated at around 12,000 lbs when accounting for the volume of water displaced as it rises. This force reflects the buoyancy principle, where the upward force equals the weight of the displaced water. Attempting to hold the boat down would indeed require a significant amount of force, potentially straining a rope if no stretch is assumed. Understanding these dynamics is crucial for accurately assessing the forces at play in such scenarios.
ckrizan
Messages
2
Reaction score
0
Can anyone tell me how much upward force a boat (say 24 feet x 8 feet, weighing 4000 lbs) exerts as it rises 1 foot on an incoming tide? My son asked me whether or not somone could hold the boat down as it tried to rise and I thought not but can't quite figure out how to quantify how hard it would be to try. Is it something that would strain a rope if you tried to hold it down (assuming no stretch)? Is "force" even the right term? Should I be asking how much work is done?

Thanks.
 
Engineering news on Phys.org
ckrizan said:
Can anyone tell me how much upward force a boat (say 24 feet x 8 feet, weighing 4000 lbs) exerts as it rises 1 foot on an incoming tide? My son asked me whether or not somone could hold the boat down as it tried to rise and I thought not but can't quite figure out how to quantify how hard it would be to try. Is it something that would strain a rope if you tried to hold it down (assuming no stretch)? Is "force" even the right term? Should I be asking how much work is done?

Thanks.

Welcome to the PF. You can read more about bouyancy under the topic of Archimedes Principle:

http://en.wikipedia.org/wiki/Archimedes_principle

The force exerted on a floating object is equal to the weight of the water displaced. So to answer your son's question, you will need to figure out the extra volume of water that gets displaced as you hold the boat in place and the water rises, and then figure out how much that extra volume of displaced water weighs.
 
If the water were up to the gunnels, a little downward force would sink it.
 
Similarily you could ask him how much force it would take to "pull" a boat down 1 foot.

hint: Let's say you have a 12'x4' boat. Then you have 48 cubic feet of displaced water. That's just under 3000 lb of displaced water...
 
Thanks everyone. So for I guess for my 24x8 example (assuming it's squared-off), that would be about 12,000 lbs of force. That's a lot.

Thanks again.
 
Thread 'I need a concave mirror with a focal length length of 150 feet'
I need to cut down a 3 year old dead tree from top down so tree causes no damage with small pieces falling. I need a mirror with a focal length of 150 ft. 12" diameter to 36" diameter will work good but I can't think of any easy way to build it. Nothing like this for sale on Ebay. I have a 30" Fresnel lens that I use to burn stumps it works great. Tree service wants $2000.
Hi all, i have some questions about the tesla turbine: is a tesla turbine more efficient than a steam engine or a stirling engine ? about the discs of the tesla turbine warping because of the high speed rotations; does running the engine on a lower speed solve that or will the discs warp anyway after time ? what is the difference in efficiency between the tesla turbine running at high speed and running it at a lower speed ( as fast as possible but low enough to not warp de discs) and: i...
Back
Top