Can You Solve These Prime Number Proofs?

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Just a couple questions that I'd appreciate any help on.

1. if [(2^d) - 1] is prime, prove that d is prime as well.

2. Prove that (p-1)C(k) is congruent to (-1)^k mod p.

I've started them both but ended up getting stuck.
Any ideas?

Thanks
 
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1. These look like textbook questions and so should go into the appropriate section of the Science Education Zone.

2. To get help, you must first show what you've tried and where you're stuck.
 
JdotAckdot said:
I've started them both but ended up getting stuck.
Any ideas?

Yes, show us how you started and where you got stuck. The responses by CarlB and AKG have been "soft deleted" and will be restored once you have shown an attempt at the problem.
 
first Q is simple

if d is even .2^d is 2^2n .even no: are {expressed in this form } ie 4^n if n is prime i.e. n>or=2 4^n is > or = 16. 4^n -1 is never a prime no. { eg 16-1=15}
so n cannot be even.thus we can prove by indirect method.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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