- #1

nhrock3

- 415

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"number 'e' is found almost accurately in a certain computer,and we can consider it as accurate.so each power of it also accurate. so we left to calculate the fracture ie

[tex]e^x=e^{[x]}e^{x-[x]}[/tex] "the question goes on

how is [tex]e^x=e^{[x]}e^{x-[x]}[/tex] a fracture

?

square cols represent the whole value