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Capacitance in series

  1. Jun 1, 2010 #1
    1. ok, there are 2 capacitors in series in a DC network, with A having a capacitance of 1.6 nanofarads and B having 5 nanofarads capacitance, but how do i find the charge, voltage and energy stored in each if the supply voltage is 24 volts. if anyone could help within the day that would be great. thanks! :biggrin:
     
  2. jcsd
  3. Jun 1, 2010 #2
    just to say that im asking u guys just to check the figures because ive got a set of answers here.
     
  4. Jun 1, 2010 #3
    what is your approach on the problem? Where are you struck up? Could you show the steps you followed and relevant equations used.
     
  5. Jun 1, 2010 #4

    vk6kro

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    Science Advisor

    Here is an approach to solving this type of problem.

    First, get the total capacitance of the two capacitors in series.
    This is given by 1/Ct = 1/C1 + 1/C2

    Now use Q = Ct * V to get the charge which charged the capacitors. V is the supply voltage.

    The charge on each of the capacitors is the same as the total charge.

    So, rearrange the formula now to get V = Q / C. (Q in Coulombs. C in Farads)

    You know each of the capacitor values and you know the charge, so you can work out the voltages across each of the capacitors.
    Notice that the voltages must add up to the supply voltage.
     
    Last edited: Jun 1, 2010
  6. Jun 2, 2010 #5
    yes just checked my answers with that method and it's worked out allright. thanks for that quick response!
     
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