Capacitor Charging, Energy Flow

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SUMMARY

The discussion focuses on the energy flow during capacitor charging in two scenarios involving a steady voltage source from a battery (Vb) and three capacitors (C1, C2, C3) with equal capacitance. In Scenario A, Vb is connected in parallel with Vc1 through resistor R1, while in Scenario B, Vc2 is connected in parallel with Vc3 through resistor R2. The voltage relationships indicate that after charging, Vb equals Vc1, Vc3, and Vc2. The primary inquiry is whether to calculate energy flow using Ohm's Law and the formula I²R or to apply capacitor energy calculations for C1 and C3.

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kboi
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Gentlemen and Ladies - Requesting a little clarification on this.

Heres the setup: I have "steady" voltage source - In this case from a battery (Vb)
Have three capacitors (C1, C2, C3). Have 2 Resistors R1 and R2.

Here are the relationships:
Capacitance Voltage Resistance
C1 = C2 = C3 1/2Vb = Vc1 = Vc3 = 1/3Vc2 R1 = R2

Two scenarios:
Scenario A:
Connect Vb in Parallel with Vc1 placing R1 in between.

Scenario B:
Connect Vc2 in Parallel with Vc3 placing R2 in between.

Initial Potential Difference in Scenario B is Double that of Scenario A.

++++++++++++++

Here are the Voltage relationships AFTER "running" the above Scenarios.
Vb = Vc1 = Vc3 = Vc2

Even though we have raised C1 and C3 to the same Voltage - My question comes down to how much energy actually flowed through R1 and R2 during this process?

Would we calculate this using Ohms Law and Measure the Current and Voltage at specific intervals and then use I^2R or should we just use capacitor energy calculations on C1 and C3.

The heart of the question is what's the relation between "energy flows" between the 2 Scenarios?
 
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It would help if you provided diagrams to remove ambiguities such as
kboi said:
Connect Vb in Parallel with Vc1 placing R1 in between.
Both arrangements shown below start with two batteries in parallel and then a resistor is placed "in between". :oldconfused:

Circuits.png
 

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