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Four identical capacitors are connected with a resistor in two different ways. When they are connected as in part a of the drawing, the time constant to charge up this circuit is 0.67 s. What is the time constant when they are connected with the same resistor as in part b?

The pictures included are http://edugen.wiley.com/edugen/courses/crs1000/art/qb/6e/ch20p_99.gif

I really have no idea what I'm doing here. My work is as follows:

T=RC

Ta=RCa, Tb=RCb

Ca=Cs1+Cs2

1/Cs=1/C+1/C

1/2/C=1/2C=2C

1/Cb=1/Cp+1/C

Cb=1/(1/Cp+1/C)

Cp=C+C=2C

Cb=1/(3/2C)=s/3C

Ta=R(2)(C)

Tb=R(2/3)(C)

Tb/Ta=R(2)(C)/R(2/3)(C)

Tb=3Ta

If anyone could help me with what I did wrong/what I need to fix, I'd appreciate it

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# Homework Help: Capacitors and Dialectric Constant

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