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Capacitors and Dialectric Constant

  1. Mar 20, 2006 #1
    Capacitors, Hard Problem

    Four identical capacitors are connected with a resistor in two different ways. When they are connected as in part a of the drawing, the time constant to charge up this circuit is 0.67 s. What is the time constant when they are connected with the same resistor as in part b?

    The pictures included are [​IMG]

    I really have no idea what I'm doing here. My work is as follows:

    T=RC
    Ta=RCa, Tb=RCb
    Ca=Cs1+Cs2
    1/Cs=1/C+1/C
    1/2/C=1/2C=2C
    1/Cb=1/Cp+1/C
    Cb=1/(1/Cp+1/C)
    Cp=C+C=2C
    Cb=1/(3/2C)=s/3C
    Ta=R(2)(C)
    Tb=R(2/3)(C)
    Tb/Ta=R(2)(C)/R(2/3)(C)
    Tb=3Ta

    If anyone could help me with what I did wrong/what I need to fix, I'd appreciate it
     
    Last edited: Mar 20, 2006
  2. jcsd
  3. Mar 21, 2006 #2

    berkeman

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    Staff: Mentor

    I didn't work through your equations, but basically you need to calculate the total capacitance in each situation to determine the RC time constant.

    For the first circuit, the total combination of capacitance is C, right? Each leg is half of C, and the two parallel C/2 legs together gives you back a whole C, right? So the time constant for the first circuit is RC.

    You need to then calculate the total combination of capacitance for the second circuit. The two caps in parallel are easy -- what is the combination of the two C caps in parallel? And then you end up with 3 caps in series -- the combo of the two parallel caps, plus the two C caps. What is the equation for combining caps in series? Just combine the equivalent capacitance from the two parallel C caps and the other two series C caps, and you will get an equivalent total capacitance. That will give you the relative time constant compared to the original RC from the first circuit. Makes sense?
     
  4. Mar 21, 2006 #3
    I'm still confused. I tried working through what you said but I don't come up with anything...
     
  5. Mar 21, 2006 #4

    berkeman

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    Staff: Mentor

    You've got parts of it right in the work that you showed.

    What is the equivalent capacitance of the caps in the first circuit arrangement? (parallel combo of two series C)

    What is the equivalent capacitance of the caps in the second circuit arrangement? (two parallel C then in series with two other C)

    What is the ratio between these two equivalent capacitance values? That will be the ratio of the time constants....
     
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