Capacitors/Resistors/time constant current

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The discussion revolves around a circuit involving two capacitors charged by a 14.0 V battery, which is then disconnected, and the circuit is closed for 1.80 ms. Participants are tasked with calculating the remaining charge on each capacitor (3 µF and 2 µF) and the current flowing through the resistor. The relevant equations provided include V=IR and q=Q(1-e^-t/RC), indicating the need to determine the effective capacitance for the calculation. The user expresses uncertainty about how to initiate the problem-solving process. The discussion highlights the importance of understanding time constants and capacitor behavior in RC circuits.
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Homework Statement



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The given pair of capacitors in the figure below are fully charged by a 14.0 V battery. The battery is disconnected and the circuit closed. Answer the following after the circuit has been closed for 1.80 ms.

Homework Equations



V=IR
q=Q(1-e^-t/RC)

The Attempt at a Solution



I know we have to at least use the second equation above but I just don't know how to start this problem.
 

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whoops! Forgot the include the questions in the post, haha:

a) How much charge remains on each capacitor (3 and 2 microF)?

b) What is the current in the resistor?

Thanks guys.
 
What is the effective capacitance, which you can use in place of the two capacitors?
 

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