Car Passes Bus: Velocity Ques. Answered in 5 Secs

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A car and a bus are initially 20 meters apart, with the car traveling at 10 m/s and the bus at 20 m/s. After accelerating at 5 m/s² for 5 seconds, the car reaches a speed of 35 m/s and covers a distance of 112.5 meters, while the bus travels 100 meters. The distance between the two vehicles decreases to 7.5 meters after 5 seconds. The car's relative speed to the bus is 15 m/s, leading to a calculation that it takes an additional 1.6 seconds to completely pass the bus, totaling approximately 6.6 seconds for the entire maneuver. The calculations confirm that the car successfully passes the bus within this time frame.
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1. Homework Statement
A car of length 4m and a bus of length 12m are traveling in the same direction 20m apart. The cars current velocity is 10m/s and the buses current velocity is 20m/s, the car suddenly starts to accelerate at 5m/s^2 and stops accelerating after 5 seconds. How long does it take the car to completely pass the bus?2. Homework Equations
d=Vit + 1/2at^2
i'm not sure about other ones that can be used here...3. The Attempt at a Solution
i figured (not sure if it's right though) the bus travels 100m in 5s and the car travels 112.5m in the same amount of time. So the original distance of 20m between the car and the bus has lessened to 20m - 12.5m = 7.5m. So the distance between the bus and the car is now 7.5m. Not sure how to proceed from here...hints? Thanks.
 
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What is the velocity of the car after 5 seconds?
Problem says that the car and bus are 20 m part. But it is not clear form which point to which point
 
The velocity of the car after 5 seconds is 10m/s (back to its original velocity).
 
1irishman said:
The velocity of the car after 5 seconds is 10m/s (back to its original velocity).
This is not correct. Use
v = vo + at
 
are my distances wrong then?
 
1irishman said:
are my distances wrong then?
They are correct.
 
Okay i have:
if vi of car=10m/s
a=5m/s^2
t=5s
then vf=35m/s
Is that right so far? thanks.
 
1irishman said:
Okay i have:
if vi of car=10m/s
a=5m/s^2
t=5s
then vf=35m/s
Is that right so far? thanks.
Yes. It is correct.
 
okay...i think I've solved it:
since cars new constant speed is 35m/s and distance is 23.5m.
The relative speed to the bus should be 15m/s.
So, v=15m/s
d=23.5m
then t=1.6s
So, it should take the car 6.6s to pass the bus right?
 
  • #10
1irishman said:
okay...i think I've solved it:
since cars new constant speed is 35m/s and distance is 23.5m.
The relative speed to the bus should be 15m/s.
So, v=15m/s
d=23.5m
then t=1.6s?
So, it should take the car 6.6s to pass the bus right?
v = d/t.
Then t = ?
 
  • #11
1.6s plus 5s
 
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