What is the deceleration and duration of a car skidding at 60 mi/h?

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To determine the deceleration and duration of a car skidding at 60 mi/h, the problem requires identifying known variables and applying kinematic equations. The car skids 176 ft after braking, and with constant deceleration, the initial speed is 88 ft/s. The equation v^2 = u^2 + 2ad can be used to find acceleration, while D = T(vf + vi)/2 helps calculate time. It's important to note that the direction of acceleration is negative due to deceleration. Proper application of these equations will yield the required values for deceleration and skid duration.
mailman85
Please help me with this problem. I have tried many things to solve it, but there doesn't seem to be enough supplied information. I'm sure I'm just overlooking something. Thanks.

A car traveling at 60mi/h (88ft/s) skids 176 ft after its breaks are suddenly applied. Under the assumption that the braking system provides constant deceleration, what is that deceleration? For how long does the skid continue?
 
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Hi mailman85, welcome to Physicsforums!

First this problem is suppose to be at the Physics section.

Anyway.

First, identify all the known variables. Then identify all the five kinematics equations. Now plug the known variables into one of the kinematic equation.

One thing you have to make sure is that the direction of the acceleration is negative.
 
You can use the following equation for acceleration. You know the initial speed the final speed and the distance. That is enough to solve for both time and acceleration.

D=T(vf+vi)/2 can be used to find time.

You should be able to find the equation for for acceleration.

hope this helps
 
Try v^2 = u^2 + 2ad
 
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