Can Cross Product Methods Yield Different Cartesian Equations for a Plane?

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The discussion addresses the method of deriving the Cartesian equation of a plane from its vector form using cross products. It confirms that the components A, B, and C of the plane's normal can indeed be obtained through the cross product of two vectors. However, differences in results can arise when comparing methods, such as substitution/elimination. It emphasizes that while the normal vector identifies the orientation of the plane, it does not uniquely define it, as multiple parallel planes share the same normal. The correct approach involves using the dot product of the normal vector with a position vector to establish the plane's equation accurately.
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this is just a simple question

For a plane in vector form, can the cartesian equation (Ax+By+Cz+D=0) be found by finding the cross product of the two vectors? My understanding is that A, B and C are the components of the normal of the plane, which can be found by doing the cross product. However, upon comparing my answers to those of a classmate, I discovered our answers were different, he used a method of substitution/elimination.
 
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Getting the normal to the plane isn't enough since any vector is normal to an infinite number of parallel planes. You must take the dot product of the plane normal vector with the position vector from a reference point on the plane to an arbitrary point on the plane (x,y,z) to get the equation. Your two answers should be the same, except that his may differ from yours by a multiple of the plane equation.
 
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