Cell and membrane volume physics

AI Thread Summary
The discussion focuses on calculating the volume of a human cell modeled as a sphere, with a diameter of 10 μm and a membrane thickness of 4.2 nm. The volume of the cell is correctly calculated as approximately 523.60 μm^3 using the formula for the volume of a sphere. However, confusion arises in calculating the volume of the cell membrane, as the initial attempt mistakenly uses the membrane thickness as the radius. The correct approach involves calculating the volume of a spherical shell, taking into account the outer radius of 5 μm and the thickness of 4.2 nm. Understanding the geometry of the problem is crucial for accurate calculations.
Akewal
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Homework Statement


A typical human cell is approximately 10 μm in diameter and enclosed by a membrane that is 4.2 nm thick. To simplify the calculations, model the cell as a sphere.
1) What is the volume of cell? (in μm^3)
2) What is the volume of cell membrane? (in μm^3)
3) Percent cell volume the membrane occupies

Homework Equations


V= 4/3*pi*r^3

The Attempt at a Solution


I knew the volume of sphere, so I could easily solve for number 1 Because 10 was the diameter, I divided it by 2 which gave me a radius of 5.
1) 4/3*pi*125= 523.60μm^3
2) This is where I got stuck. I converted 4.2 nm to μm (multiplying 4.2 with 0.001), and used the volume formula, with .0042 μm as my r. The answer is wrong!

What I am doing wrong?
 
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Hello Akewal, ##\qquad##:welcome:##\qquad##!

The way you describe it, you calculated the volume of a sphere with a radius of 4.2 nm ...

If you make a coarse sketch, you see that you are after the volume of a shell with radius 5 ##\mu##m and a thickness of 4.2 nm ... A different beast !
 
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