Center of Mass of a System Problem

AI Thread Summary
The problem involves calculating the center of mass for a system of two particles with given position vectors. For particle m1, the position is defined as r1(t) = (txhat - t^2yhat)m, and for particle m2, it is r2(t) = (txhat + t^3yhat)m. The user attempts to find the center of mass using the formula m1 x1(1) + m2 x2(1) / (m1 + m2) but expresses uncertainty regarding the inclusion of both x and y components. The discussion highlights the need to consider both components for accurate calculations of position, velocity, and acceleration. Clarification on how to properly incorporate both components is sought.
catstevens
Messages
4
Reaction score
0

Homework Statement



From an inertial reference frame S, the vector position of a particle of mass
m1 = 1kg is given by r1(t)=(txhat - t^2yhat)m.
The vector position of a particle m2=2m1 is given by r2=(t)=(txhat +t^3yhat)m

Assume t=1second
Find the position, the velocity and the acceleration of the center of mass of the composite system: xCM vCM a CM


Homework Equations



m1 x1(1) + m2 x2(1) / m1 + m2


The Attempt at a Solution



3xkg/ 3kg = 3x-direction

velocity = x
acceleration = 0

I do not think this is right, could some one help?

 
Physics news on Phys.org
There is an x and y component to the position vector. You need to take both into consideration.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top