Proving Magnitude of Position Vector for Centre of Mass

AI Thread Summary
The discussion centers on proving the magnitude of the position vector for the center of mass using the equation M2R2 = M∑ri2 - (1/2)∑mi mjrij2. The user expresses uncertainty about how to approach the problem, starting with the equation F = MR''. They attempt to derive R'' but feel they may be going off track. The response highlights a failure in their LaTeX code, suggesting that reposting the work could facilitate better assistance. Clarity in mathematical representation is crucial for effective problem-solving in this context.
metgt4
Messages
34
Reaction score
0

Homework Statement



Prove that the magnitude R of the position vector for the centre of mass from an arbitrary origin is given by the equation

M2R2 = M\summiri2 - (1/2)\summimjrij2

Homework Equations



F = MR''

F = p'

p = \summjrj'



The Attempt at a Solution



I'm not quite sure where to start with this, but this is what I've tried so far:

F = MR''

R'' = \frac{F}{M} = \frac{p&#039;}{M} = \frac{(\summ<sub>j</sub>r<sub>j</sub>&#039;)&#039;/M<br /> <br /> And that&#039;s about where I think I go wrong. Am I on the right path, or am I waaayyy off?
 
Physics news on Phys.org
We cannot see what you have done because your LateX code failed. Try re-posting and someone might be able to help you.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top