Centrifugal forces + pressure and CG

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Like density of liquid and solid are the same, I think centrepetal forces are the same for liquid and solid, so all centripetal forces cancel themselves and I don't show them on drawings.

Now, forces that I drawn on my last drawings are only forces from pressure of liquid, C and F forces like we spoke before. Like W is constant I don't see others forces. In my second drawing if I put forces for cancel all torques, the support of the system must see a force to the left and up. I think it's logical to say sum of torques is zero. For me, the square part of solid adding reduce C forces at external circle.

It's a difficult problem but interresting too, if someone can help me to pose equations I can be resolve it. The difficulty for me it's to understand what's happen in reality.
 
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If you are using centripetal analysis you must use accelerations and Newtons laws.

If you want to do force analysis you must use D'Alembert's method.

I have noted this before.

I have also noted that I do not understand your diagrams or yours arrows in particular.
 
I drawn with more details on forces like I think there are. I think it's not necessary to use Newton or Alembert method because my error is enormous when I see sum of forces. I think I forget something in the system.
In the drawing, red forces are forces from centripetal effect, like solid and liquid have same density, sum of these forces are zero.
Green forces are only pressure of liquid but without the centripetal forces (red color for that). We have F and C forces like we see before. For me torques from Fa, Fb and Fc must be to 0 because this system can't give energy from nothing. So I need anothers forces for compensate sum of Fa+Fb+Fc (in vector) but sum of c1+c2+c3+c4+c5 don't do that, these forces are at left too. For me c4 and c5 are lower because there is less water in a radius length due to the presence of solid, solid which give only centripetal forces not pressure. What another forces are in the system ?
 

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So with the shape in the drawing, in a small part of rotation F1>F2, this give a torque ? F2 move more than F1 so how torque can cancel ?
 

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