Centripetal Acceleration lab graph

AI Thread Summary
The discussion revolves around the relationship between centripetal acceleration and gravitational force in a lab experiment involving circular motion. The experiment involves spinning a stopper attached to a string and weights, maintaining a constant angular velocity. Participants clarify that centripetal acceleration, calculated using the formula a = v^2/r, is independent of gravitational force. The misconception that centripetal acceleration equals gravitational acceleration is addressed, emphasizing that they are distinct concepts. Understanding this difference is crucial for accurately interpreting the lab results.
sarujin
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I have a lab that needs a graph, and my calculations seem logical, but I need some affirmation. In this lab we spun a string with a stopper attached at one end and some weights at the other end. We had to keep a part of the string at the same point while spinning and therefore it moved at a constant angular velocity, right? ( http://www.richardson.k12.tx.us/schools/phs/staff/academ/klindsay/Web/lindsay/Pre-AP/MomRot/Lab%20Circ%20Mot.htm ) is the lab, if you need more explanation of the lab. In our calculations we have to graph Centripetal Acceleration vs. omega, the angular velocity. Using the equation F = ma... the force is weight (pulling on the stopper spinning), which is mg. Then mg = ma, then g = a.

In other words, if something is going at a constant velocity around your head in a circle and not falling, centripetal acceleration equals acceleration due to gravity?

Thanks!
 
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If centripetal acceleration equals acceleration due to gravity, then it would stay where it was, in a circle (because its centripetal acceleration)?
 
Originally posted by sarujin
In other words, if something is going at a constant velocity around your head in a circle and not falling, centripetal acceleration equals acceleration due to gravity?

a = v^2/r

centripital acceleration has absolutely nothing to do with gravitational force.
 
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