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[SOLVED] Centripetal Acceleration Part II
(From previous question) In order for a satellite to move in a stable circular orbit of radius 6689 km at a constant speed, its centripetal acceleration must be inversely proportional to the square of the radius of the orbit.
What is the speed of the satellite? The G is 6.67259e-11 and the mass of the Earth is 5.98e24kg.
The answer to this was 7723.55 m/s.
Part II:
Find the time required to complete one orbit. Answer in units of h.
The book only gives one equation for T referencing orbits, which is v=2pir/T
v=2pi/T
7723.55 = 2pi/T
7723.55T = 2pi
T = 2pi/7723.55
T = .000814
I think the homework system even laughed at me when I entered that answer :)
Homework Statement
(From previous question) In order for a satellite to move in a stable circular orbit of radius 6689 km at a constant speed, its centripetal acceleration must be inversely proportional to the square of the radius of the orbit.
What is the speed of the satellite? The G is 6.67259e-11 and the mass of the Earth is 5.98e24kg.
The answer to this was 7723.55 m/s.
Part II:
Find the time required to complete one orbit. Answer in units of h.
Homework Equations
The book only gives one equation for T referencing orbits, which is v=2pir/T
The Attempt at a Solution
v=2pi/T
7723.55 = 2pi/T
7723.55T = 2pi
T = 2pi/7723.55
T = .000814
I think the homework system even laughed at me when I entered that answer :)