Centripetal Force of merry-go-round

AI Thread Summary
A 22 kg child on a merry-go-round rotating at 40 rpm, positioned 1.25 m from the center, exerts a centripetal force of 482.9 N, which is 21.95 times her weight. In contrast, if the same child rides a merry-go-round at 3 rpm and 8 m from the center, the required centripetal force drops to 17.36 N, or 0.789 times her weight. The discussion highlights the significant difference in centripetal force based on rotation speed and distance from the center. Additionally, there is a note that the topic is more suitable for the K12 section rather than a college forum. Overall, the calculations demonstrate how centripetal force varies with different parameters in rotational motion.
nautica
a) A 22 kg child is riding a merry-go-round that is rotating at 40 rpm. What centripetal Force must she exert to stay on if she is 1.25 m from its center?

40 rpm = 4.19 rad/s
r = 1.25 m

Ac = (4.19 rad/s)^2 * (1.25 m) = 21.95 m/s^2

F = (22 kg) * ( 21.95 m/s^2) = 482.9 N


b) What cent Force does she need to stay on one that rotates at 3 rpm if she is 8 m from its center

3 rpm = .314 rad/s

Ac = (.314 rad/s)^2 (8 m) = .789 m/s^2

Force = (22 kg) (.789 m/s^2) = 17.36 N

c) compare each force with her weight.

Force 1 is 21.95 x's her weight
Force 2 is .789 x's her weight

how does this look
thank
nautica
 
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Looks good to me.
 
Cool, thanks

Nautica
 
This is the wrong forum. This should be posted in K12 section not College.
 

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