Centripetal force on a stunt pilot

AI Thread Summary
A stunt pilot diving vertically at 150 m/s must consider centripetal force when pulling out into a circular path. To ensure the force does not exceed 6g, the minimum radius of the circle can be calculated using the formula r = mv²/a, where 'a' is the acceleration due to gravity multiplied by 6. The apparent weight of the pilot at the lowest point of the circle is determined by the net force equation R = mg + 6g. Clarifications on whether the dive is powered or unpowered may affect calculations, particularly regarding speed variations. The discussion highlights the importance of understanding the distinction between force and acceleration in such scenarios.
nokia8650
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A stunt pilot who has been diving vertically at 150m/s pulls out to dive into a circle in the vertical plane.

a)What is the minimum radius of the circle, if the force on the pilot is not to exceed 6g.

b)If the pilot has a mass of 80kg, what is the apparent weight of the pilot at the lowest point of the circle?My solution:

a)6g = mv^2/r
r= 383*mass metres

b) 6g = R-mg
R= g(6+80)
=844N

Is the above correct? The answer to part a) seems abit too large to me!

Thank you very much for any assistance, I really appreciate it.
 
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nokia8650 said:
A stunt pilot who has been diving vertically at 150m/s pulls out to dive into a circle in the vertical plane.

a)What is the minimum radius of the circle, if the force on the pilot is not to exceed 6g.

b)If the pilot has a mass of 80kg, what is the apparent weight of the pilot at the lowest point of the circle?

Hi nokia8650! :smile:

i] when people say a force of 6g, they mean an acceleration of 6g … so you can forget the mass in part a)

ii] is this an unpowered dive, so that the speed increases, or a powered dive at exactly the same speed throughout? :confused:
 
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