Cepheid Variables and the Small Magellanic Cud

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SUMMARY

The discussion focuses on calculating the distance to the Small Magellanic Cloud (SMC) using the properties of Cepheid variables. The known Cepheid variable δ Cephei has a parallax of 0.0033 arcseconds, translating to a distance of 303 parsecs. A second Cepheid in the SMC appears 11.5 magnitudes fainter than δ Cephei, indicating it is further away. The relationship between apparent magnitude and distance is established through the equation m-M=5log(d)-5, allowing for the calculation of the SMC's distance based on the luminosity of the Cepheids.

PREREQUISITES
  • Understanding of parallax measurements in astronomy
  • Familiarity with the concept of Cepheid variables and their luminosity
  • Knowledge of astronomical magnitude and its logarithmic scale
  • Proficiency in using the distance modulus formula m-M=5log(d)-5
NEXT STEPS
  • Study the application of the distance modulus in various astronomical contexts
  • Learn about the role of Cepheid variables in measuring cosmic distances
  • Explore the relationship between luminosity and distance in stellar astrophysics
  • Investigate the Small Magellanic Cloud's significance in galactic studies
USEFUL FOR

Astronomy students, astrophysicists, and anyone interested in distance measurement techniques in cosmology will benefit from this discussion.

Berdi
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Homework Statement



The Galactic Cepheid variable δ Cephei has a parallax of 0.0033 arcseconds. An astronomer locates another Cepheid, with the same period as δ Cephei, in the Small Magellanic Cloud (SMC). If this Cepheid appears 11.5 magnitudes fainter than δ Cephei, calculate the distance to the SMC.

Homework Equations



[tex]m-M=5\log(d)-5[/tex]

[tex]L=4\pi R^2F[/tex]

[tex]m_{1}-m_{2}=2.5\log( L_{2}/L_{1})[/tex]

The Attempt at a Solution



Well, I know the distance to the first Cepheid, as it is 1/Parallax = 303pc. I understand that the same period means the same luminosity, and that 11.5 fainter will mean that the m will be actually 11.5 larger, But I'm unsure how this will help me. Unless you say that [tex]m_{1}-m_{2}[/tex] is 11.5 and change the L's for 1/d^2 ?
 
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The absolute magnitudes of the two variables are the same (same period)
If one appears 11.5 mag fainter then it's obvisouly further away.

The first equation tells you have far away an object would have to be to be less bright by (m-M) magnitudes compared to an object 1pc away.

Another way to think of it. Work out the relative apparent luminosity of the two stars, then if the second one was 1/4 as bright it would have to be twice as far away.
 

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