Chain rule for several variables: Implicit diff.

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SUMMARY

The discussion focuses on finding the derivative dz/dx for the implicitly defined function Z, given by the equation (z^2)x + 3xy^2 + e^((y^2)z) = 4. The correct application of the chain rule for several variables is confirmed, with the partial derivatives calculated as Fx = z^2 + 3y^2 and Fz = 2zx + (y^2)e^((y^2)z). The final expression for dz/dx is accurately derived as dz/dx = (z^2 + 3y^2) / [2zx + (y^2)e^((y^2)z)].

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soe236
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Homework Statement


Z is defined implicitly as a function of x,y by equation (z^2)x + 3xy^2 + e^((y^2)z) = 4. Find dz/dx

Homework Equations


dz/dx = -Fx/Fz

The Attempt at a Solution


Fx= z^2 + 3y^2
Fz=2zx+(y^2)e^((y^2)z)
dz/dx= (z^2+3y^2)/[2zx+(y^2)e^((y^2)z)]

I'm not sure if I used the partial derivatives correctly, and a little unsure about the procedure as well. Someone please check that and tell me if it's correct. Thankyou
 
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soe236 said:
(z^2)x + 3xy^2 + e^((y^2)z) = 4. Find dz/dx

Fx= z^2 + 3y^2
Fz=2zx+(y^2)e^((y^2)z)
dz/dx= (z^2+3y^2)/[2zx+(y^2)e^((y^2)z)]

Hi soe236!

Looks good to me. :biggrin:
 
Thank you!
 

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