Changing masses on an atwood machine

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SUMMARY

The discussion centers on the dynamics of an Atwood machine with two masses, initially equal at 5 kg each, and the effect of an additional 1 kg mass (a frog) jumping onto one side. When the frog lands on mass 1, the system is no longer in equilibrium, resulting in mass 1 accelerating downward at approximately 1.8 m/s² due to the net force calculation. The tension in the string is recalculated to be 58 N based on the new mass configuration. The conversation also raises questions about the system's behavior immediately after the equilibrium is disturbed and the implications of adding mass during observation.

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  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of tension and net force
  • Basic knowledge of kinematics and acceleration calculations
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  • Study the effects of changing mass on Atwood machines
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  • Explore advanced kinematic equations for varying mass scenarios
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overthewater
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An example of this kind of a problem would be a frictionless, massless pulley holding two equal masses(say, 5kg each). But then, an additional mass is added to one side (ie, a frog jumping on to mass 1, 1 kg). What would happen to the system? What if the frog jumps off?Initially, I know that the system has a net force of 0. F(net) = T -Fg while T=Fg.
It is not accelerating.
But after the frog jumps on, the system is no longer in equilibrium and mass 1 accelerates downward because the force of gravity on the "new" mass 1 (5+1= 6 kg) is larger than the tension in the string . So, mass 1 would be accelerating downwards at approximately 1.8 m/s^2. This is because a = (m1*g-m2*g)/(m1+m2). And tension, calculated using mass 2 where T>Fg would be T=Fnet+Fg=5*1.8+5*9.8= 58N.


But I don't think that the actual test question would be this simple. Is there anything different I need to look at? For example, does the system still have a constant acceleration just after the equilibrium is disturbed? Does the fact that a mass was added during our observations cause the situation to differ from if we were to look at it from two different events (ie, before the frog, when the masses were equal, and then a situation where one mass is greater than the other. Then comparing the two events)
 
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Hello water, welcome to PF :)
Use the template: it's mandatory in PF and it helps you to order your thinking.

Check your calculation: g/11 is not 1.8 m/s2.
(Otherwise, what you do seems correct to me).

Read what you typed before posting; your last paragraph is totally unclear.

And when the frog jumps off (sideways): what is then the net force on each mass ?
 

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