Changing the Subject of a Formula

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The discussion focuses on converting the formula for Celsius to Fahrenheit. The original formula presented is C = (F + 40)(5/9) - 40, but the user struggles with the algebraic manipulation to isolate F. A key mistake identified is the incorrect handling of the constants during the rearrangement of the equation. The correct transformation leads to F = (C + 40)(9/5) - 40. The user acknowledges their error in the process and expresses gratitude for the clarification.
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Homework Statement



Express the formula for converting Celsius temperatures to Fahrenheit.



Homework Equations



C= (F+40)(5/9) - 40



The Attempt at a Solution




C= (F+40)(5/9) - 40
C- 40= (F+40 - 40)(5/9) - 40
(C-40)9/5= F(9/5)(5/9) - 40
(C - 40)9/5 + 40= F - 40 + 40

F= (C - 40)9/5 + 40


Answer: F= (C + 40)9/5 - 40

Could someone please explain to me why the operation signs in the (C + 40) and - 40 are opposite from the solution I came up with?
 
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LightbulbSun said:

Homework Statement



Express the formula for converting Celsius temperatures to Fahrenheit.



Homework Equations



C= (F+40)(5/9) - 40



The Attempt at a Solution




C= (F+40)(5/9) - 40
You made a mistake going from this line to the one below.
C- 40= (F+40 - 40)(5/9) - 40
You need to add 40 to both sides.. I don't know where you've got that 40 from inside the brackets. The next line should read
C+40=(F+40)(5/9)

Now, what do you think you'd do next?
 
cristo said:
You made a mistake going from this line to the one below.
You need to add 40 to both sides.. I don't know where you've got that 40 from inside the brackets. The next line should read
C+40=(F+40)(5/9)

Now, what do you think you'd do next?

OH! I know what I did wrong. I started from within the brackets first and got rid of the +40 next to the F instead of getting rid of the -40 on the outside. Now I see where I went wrong. Thank you.
 
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