The Hall voltage across a 0.800-mm-thick conductor in a 1.30 T magnetic field is 3.2 uV when the current is 12.0 A. What is the charge carrier denisty in the conductor (in m-3). I was using the equation Vh=IB/ned where Vh is the Hall voltage I is the current B is the magnetic field n is the charge-carrier density e is the charge of an electron and d is the thickness I rearranged to get n=IB/Vhed and evaluated to get 3.806*1025m-3 But this came up wrong on the assignment and it looks like an unreasonable answer. I think I need additional values but basically this entire question is really confusing me. Thanks for the help!