Charge conjugation in Dirac equation

Click For Summary
SUMMARY

The discussion focuses on the mathematical relationship in charge conjugation within the context of the Dirac equation, specifically the equation $(C^{-1})^T\gamma ^ \mu C^T = - \gamma ^{\mu T}$. Here, $C$ is defined as $U=C \gamma^0$, where $U$ is a non-singular matrix. The significance of this relationship is demonstrated through the transformation of the Dirac equation, leading to the conclusion that the charge conjugated field $\psi_{c} \equiv \mathcal{C}\psi$ describes a Dirac particle with opposite charge. The derivation can be further explored in Sakurai's "Advanced Quantum Mechanics."

PREREQUISITES
  • Understanding of the Dirac equation and its components
  • Familiarity with charge conjugation in quantum mechanics
  • Knowledge of matrix operations, specifically transposition and inversion
  • Basic principles of quantum field theory
NEXT STEPS
  • Study the derivation of charge conjugation in Sakurai's "Advanced Quantum Mechanics"
  • Explore the implications of charge conjugation on particle physics
  • Learn about the role of non-singular matrices in quantum mechanics
  • Investigate the properties of gamma matrices in different representations
USEFUL FOR

This discussion is beneficial for theoretical physicists, quantum mechanics students, and researchers focused on particle physics and quantum field theory, particularly those interested in the mathematical foundations of charge conjugation.

forhad_jnu
Messages
2
Reaction score
0
I need to know the mathematical argument that how the relation is true $(C^{-1})^T\gamma ^ \mu C^T = - \gamma ^{\mu T} $ .
Where $C$ is defined by $U=C \gamma^0$ ; $U$= non singular matrix and $T$= transposition.


I need to know the significance of these equation in charge conjuration .
 
Physics news on Phys.org
Start with the Dirac equation
( i \gamma^{\mu}\partial_{\mu} + e \gamma^{\mu}A_{\mu} - m) \psi = 0
Now take the complex conjugate of that and multiply from the left by some non-singular matrix \mathcal{C}, you then can write
[(i \partial_{\mu} - e A_{\mu})\ \mathcal{C}\ (\gamma^{\mu})^{*} \mathcal{C}^{-1} + m ] \ \mathcal{C}\psi = 0
Thus, if
\mathcal{C}\ (\gamma^{\mu})^{*} \mathcal{C}^{-1} = - \gamma^{\mu},
then the field
\psi_{c}\equiv \mathcal{C}\psi
describes another Dirac particle with opposite charge.
Now, if you write
\mathcal{C} = C \gamma^{0}
then your relation follows in the representation where
\gamma^{0} = ( \gamma^{0})^{T} = ( \gamma^{0})^{-1}.

Sam
 
One can see sakurai 'advanced quantum mechanics' for an elegant derivation which describes the relationship between charge conjugated wave function and original one.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 49 ·
2
Replies
49
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 16 ·
Replies
16
Views
2K