Charge different entering and leaving a resistor

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AI Thread Summary
The charge of electrons remains constant as they pass through a resistor, such as a lightbulb, despite a drop in electric potential. While energy decreases due to resistance, the number of electrons entering and exiting remains the same, similar to water flowing through a pipe. The analogy illustrates that while the pressure (voltage) decreases, the flow (current) does not change. Voltage, potential, and electromotive force describe the same concept, distinct from potential energy. Understanding this relationship clarifies why charge is conserved in electrical circuits.
Seung Tai Kang

Homework Statement


Is a charge different upon its exit versus its entry into the lightbulb?

Homework Equations


PE = Vq

The Attempt at a Solution


Well, the answer is that the charge stays the same. Based on the equation above, since energy certainly gets reduced V must drop but I don't understand how charge stays the same. And the answer says it is "at a location that is lower in potential." Can someone help me grasp this idea?
 
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Think of water flowing through a pipe. The same amount of water enters the upstream end of the pipe as leaves the downstream end. This has to be true, because there is nowhere in the pipe for water to be stored. The water flow is analogous to current. However, the water pressure at the output end is lower than at the input end because some pressure is dropped due to the friction of the water with the pipe walls. The pressure is what pushes the water along and is analogous to voltage or potential.
 
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A current is a flow of electrons. Individual Electrons have constant/fixed charge.
 
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