Seung Tai Kang
Homework Statement
Is a charge different upon its exit versus its entry into the lightbulb?
Homework Equations
PE = Vq
The Attempt at a Solution
Well, the answer is that the charge stays the same. Based on the equation above, since energy certainly gets reduced V must drop but I don't understand how charge stays the same. And the answer says it is "at a location that is lower in potential." Can someone help me grasp this idea?